标签：memory time you problem nes font win names cti
题目链接：http://poj.org/problem?id=3692
| Time Limit: 2000MS | Memory Limit: 65536K | |
| Total Submissions: 7371 | Accepted: 3636 |
Description
In a kindergarten, there are a lot of kids. All girls of the kids know each other and all boys also know each other. In addition to that, some girls and boys know each other. Now the teachers want to pick some kids to play a game, which need that all players know each other. You are to help to find maximum number of kids the teacher can pick.
Input
The input consists of multiple test cases. Each test case starts with a line containing three integers
G, B (1 ≤ G, B ≤ 200) and M (0 ≤ M ≤ G × B), which is the number of girls, the number of boys and
the number of pairs of girl and boy who know each other, respectively.
Each of the following M lines contains two integers X and Y (1 ≤ X≤ G,1 ≤ Y ≤ B), which indicates that girl X and boy Y know each other.
The girls are numbered from 1 to G and the boys are numbered from 1 to B.
The last test case is followed by a line containing three zeros.
Output
For each test case, print a line containing the test case number( beginning with 1) followed by a integer which is the maximum number of kids the teacher can pick.
Sample Input
2 3 3 1 1 1 2 2 3 2 3 5 1 1 1 2 2 1 2 2 2 3 0 0 0
Sample Output
Case 1: 3 Case 2: 4
Source
题解：
最大团 = 总体 - 补图的最大独立集。
证明：最大独立集，即两两没有联系。那么它的补图，就是两两都有联系。
代码如下：
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <cstdlib> 5 #include <string> 6 #include <vector> 7 #include <map> 8 #include <set> 9 #include <queue> 10 #include <sstream> 11 #include <algorithm> 12 using namespace std; 13 const int INF = 2e9; 14 const int MOD = 1e9+7; 15 const int MAXN = 200+10; 16 17 int uN, vN; 18 int M[MAXN][MAXN], link[MAXN]; 19 bool vis[MAXN]; 20 21 bool dfs(int u) 22 { 23 for(int i = 1; i<=vN; i++) 24 if(M[u][i] && !vis[i]) 25 { 26 vis[i] = true; 27 if(link[i]==-1 || dfs(link[i])) 28 { 29 link[i] = u; 30 return true; 31 } 32 } 33 return false; 34 } 35 36 int hungary() 37 { 38 int ret = 0; 39 memset(link, -1, sizeof(link)); 40 for(int i = 1; i<=uN; i++) 41 { 42 memset(vis, 0, sizeof(vis)); 43 if(dfs(i)) ret++; 44 } 45 return ret; 46 } 47 48 int main() 49 { 50 int T, m, kase = 0; 51 while(scanf("%d%d%d", &uN, &vN, &m)&& (uN||vN||m)) 52 { 53 memset(M, true, sizeof(M)); 54 for(int i = 1; i<=m; i++) 55 { 56 int u, v; 57 scanf("%d%d", &u, &v); 58 M[u][v] = false; 59 } 60 61 int cnt = hungary(); 62 printf("Case %d: %d\n", ++kase, uN+vN-cnt); 63 } 64 }
POJ3692 Kindergarten —— 二分图最大团
标签：memory time you problem nes font win names cti
原文地址：http://www.cnblogs.com/DOLFAMINGO/p/7811313.html
