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Django 权限管理

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一 权限管理 初始版

结构

技术分享

1.创建rbac应用

2.在models中创建对象

models

技术分享
from django.db import models

class Permission(models.Model):
    """
    权限表
    """
    title = models.CharField(verbose_name=标题,max_length=32)
    url = models.CharField(verbose_name="含正则URL",max_length=64)
    is_menu = models.BooleanField(verbose_name="是否是菜单")

    class Meta:
        verbose_name_plural = "权限表"

    def __str__(self):
        return self.title

class User(models.Model):
    """
    用户表
    """
    username = models.CharField(verbose_name=用户名,max_length=32)
    password = models.CharField(verbose_name=密码,max_length=64)
    email = models.CharField(verbose_name=邮箱,max_length=32)

    roles = models.ManyToManyField(verbose_name=具有的所有角色,to="Role",blank=True)

    class Meta:
        verbose_name_plural = "用户表"

    def __str__(self):
        return self.username

class Role(models.Model):
    """
    角色表
    """
    title = models.CharField(max_length=32)
    permissions = models.ManyToManyField(verbose_name=具有的所有权限,to=Permission,blank=True)
    class Meta:
        verbose_name_plural = "角色表"

    def __str__(self):
        return self.title
models

3.基于Django admin录入权限数据

注意;需要在admin.py 中作如下操作(只针对从用admin导入数据时配置,当然也可以从数据库中直接添加)

from django.contrib import admin

from . import models


admin.site.register(models.Permission)
admin.site.register(models.User)
admin.site.register(models.Role)

4.用户登录程序

根据输入的用户名和密码得到相应的user,
根据user对象获取其拥有的角色和具有的权限并去重并且将权限表中的url放入seesion中,将这部分操作的代码抽取到service包下的init_permission.py
下的init_permission(request,user)方法中,然后在views中调用该方法即可,
- 获取当前用户具有的所有权限(去重)
- 获取权限中的url,放置到session中

技术分享
def init_permission(user,request):
    """
    初始化权限信息,获取权限信息并放置到session中。
    :param user:
    :param request:
    :return:
    """
    permission_list = user.roles.values(permissions__title, permissions__url, permissions__is_menu).distinct()
    url_list = []
    for item in permission_list:
        url_list.append(item[permissions__url])
    print(url_list)
    request.session[permission_url_list] = url_list
init_permission.py

5.编写中间件

技术分享
import re

from django.shortcuts import redirect,HttpResponse
from django.conf import settings

class MiddlewareMixin(object):
    def __init__(self, get_response=None):
        self.get_response = get_response
        super(MiddlewareMixin, self).__init__()

    def __call__(self, request):
        response = None
        if hasattr(self, process_request):
            response = self.process_request(request)
        if not response:
            response = self.get_response(request)
        if hasattr(self, process_response):
            response = self.process_response(request, response)
        return response


class RbacMiddleware(MiddlewareMixin):

    def process_request(self,request):
        # 1. 获取当前请求的URL
        # request.path_info
        # 2. 获取Session中保存当前用户的权限
        # request.session.get("permission_url_list‘)
        current_url = request.path_info

        # 当前请求不需要执行权限验证(白名单)
        for url in settings.VALID_URL:
            if re.match(url,current_url):
                return None

        permission_list = request.session.get("permission_url_list")
        if not permission_list:
            return redirect(/login/)

        flag = False
        for db_url in permission_list:
            regax = "^{0}$".format(db_url)
            if re.match(regax, current_url):
                flag = True
                break

        if not flag:
            return HttpResponse(无权访问)
rbac.py

a,获取当前访问的路径 request.path_info
b,在setting中配置不需要验证的url--白名单(人人登录后就可以访问的如login admin.*)然后调用

VALID_URL = [
    "/login/",
    "/admin.*"
]

根据正则判断当前路径是否在白名单中,白名单中的路径要严格的控制以什么开头和以什么结尾,如果是白名单return None 继续执行后面的代码
如果不是直接跳转到登录
c,不是白名单的话,则判断是否已经登录,最简单的方法就是获取当前session 看是里面的url列表是否为空,如果为空的话说明没有登录,直接
调转到登陆,不让他执行后续操作
d,url list不为空的话就说明已经登陆了,进一步看当前的访问路径是否在是否在urllist中,在的话就说明用户具有操作该url的权限否则就说明该用户没有
访问权限,直接return HttpResponse("无权访问")
注意:中间件创建完成之后。需要在settings中的MIDDLEWARE最后添加‘rbac.middlewares.rbac.RbacMiddleware‘,

MIDDLEWARE = [
    django.middleware.security.SecurityMiddleware,
    django.contrib.sessions.middleware.SessionMiddleware,
    django.middleware.common.CommonMiddleware,
    django.middleware.csrf.CsrfViewMiddleware,
    django.contrib.auth.middleware.AuthenticationMiddleware,
    django.contrib.messages.middleware.MessageMiddleware,
    django.middleware.clickjacking.XFrameOptionsMiddleware,
    ‘rbac.middlewares.rbac.RbacMiddleware‘,
]

示例一权限管理 加强

对于权限管理,不单单的只是控制能不能访问某个路径,而且还需要根据用户的权限,当用户访问某个页面时,在页面上展示什么,比如某些用户
虽然能访问首页,但是他没有添加用户的权限,这时就不能将添加按钮展现在首页,而对于具有添加用户权限的用户则需要将添加用户的按钮展示
在首页上

在访问列表页面时,是否需要判断:有无添加权限,有无删除权限,有无编辑权限;

1.在rbac下的models中添加Group类,在权限表中添加code字段和外键group

class Group(models.Model):
    """
    权限组
    """
    caption = models.CharField(verbose_name=组名称,max_length=16)
    
class Permission(models.Model):
    """
    权限表
    """
    title = models.CharField(verbose_name=标题,max_length=32)
    url = models.CharField(verbose_name="含正则URL",max_length=64)
    is_menu = models.BooleanField(verbose_name="是否是菜单")
    code = models.CharField(verbose_name="代码",max_length=16)
    group = models.ForeignKey(verbose_name=所属组,to="Group")

    class Meta:
        verbose_name_plural = "权限表"

    def __str__(self):
        return self.title


2.在rbac/service/init_permission.py/init_permission类中进行修改

结构化数据模型

data = {
            1: {
                codes: [list,add,edit,del],
                urls:[
                    /userinfo/,
                    /userinfo/add/,
                    /userinfo/edit/(\d+)/,
                    /userinfo/del/(\d+)/,
                ]
            },
            2: {
                codes: [list,add,edit,del],
                urls:[
                    /userinfo/,
                    /userinfo/add/,
                    /userinfo/edit/(\d+)/,
                    /userinfo/del/(\d+)/,
                ]
            },
            
        }
permission_list = user.roles.values(permissions__title,
                                        "permissions__code",
                                        permissions__url,
                                        permissions__is_menu,
                                        "permissions__group__id",
                                        ).distinct()



result={}
for item in permission_list:
    groupid=item["permissions__group__id"]
    code=item["permissions__code"]
    url=item["permissions__url"]

    if groupid in result:
        result[groupid]["codes"].append(code)
        result[groupid]["urls"].append(url)
    else:
        result[groupid]={
            "codes":[code,],
            "urls":[url,]
        }


print(result)


request.session[settings.PERMISSIONS_URL_DICT_KEY] = result

3.对中间件进行修改

技术分享
import re

from django.shortcuts import redirect,HttpResponse
from django.conf import settings

class MiddlewareMixin(object):
    def __init__(self, get_response=None):
        self.get_response = get_response
        super(MiddlewareMixin, self).__init__()

    def __call__(self, request):
        response = None
        if hasattr(self, process_request):
            response = self.process_request(request)
        if not response:
            response = self.get_response(request)
        if hasattr(self, process_response):
            response = self.process_response(request, response)
        return response


class RbacMiddleware(MiddlewareMixin):

    def process_request(self,request):
        # 1. 获取当前请求的URL
        # request.path_info
        # 2. 获取Session中保存当前用户的权限
        # request.session.get("permission_url_list‘)
        current_url = request.path_info

        # 当前请求不需要执行权限验证
        for url in settings.VALID_URL:
            if re.match(url,current_url):
                return None

        permission_dict = request.session.get(settings.PERMISSION_URL_DICT_KEY)
        if not permission_dict:
            return redirect(/login/)

        flag = False
        for group_id,code_url in permission_dict.items():

            for db_url in code_url[urls]:
                regax = "^{0}$".format(db_url)
                if re.match(regax, current_url):
                    request.permission_code_list = code_url[codes]
                    flag = True
                    break
            if flag:
                break

        if not flag:
            return HttpResponse(无权访问)
rbac.py

4.对views进行操作,是否页面上显示功能按钮:

方法1:在模块中进行判断

{% if "add/edit/del" in request.permission_code_list %}
  <a href="">添加/编辑/删除</a>
{% endif%}

方法二:
在views中利用面向对象

class BasePagePermission(object):
    def __init__(self,code_list):
        self.code_list = code_list

    def has_add(self):
        if "add" in self.code_list:
            return True

    def has_edit(self):
        if edit in self.code_list:
            return True
    def has_del(self):
        if del in self.code_list:
            return True

def userinfo(request):
    page_permission = BasePagePermission(request.permission_code_list)
    data_list = [
        {id:1,name:xxx1},
        {id:2,name:xxx2},
        {id:3,name:xxx3},
        {id:4,name:xxx4},
        {id:5,name:xxx5},
    ]

    return render(request,userinfo.html,{data_list:data_list,page_permission:page_permission})

5.模块中进行判断

{%   if pagepermission.has_add %}
<p><a href="">添加</a></p>
{% endif %}

示例二 菜单展示

1.在models中添加Menu对象(表)以及和Group建立起一对多的对应关系

技术分享
from django.db import models

class Menu(models.Model):
    """
    菜单组
    """
    title = models.CharField(max_length=32)


class Group(models.Model):
    """
    权限组
    """
    caption = models.CharField(verbose_name=组名称,max_length=16)
    menu = models.ForeignKey(verbose_name=所属菜单,to=Menu)


class Permission(models.Model):
    """
    权限表
    """
    title = models.CharField(verbose_name=标题,max_length=32)
    url = models.CharField(verbose_name="含正则URL",max_length=64)
    is_menu = models.BooleanField(verbose_name="是否是菜单")
    code = models.CharField(verbose_name="代码",max_length=16)
    group = models.ForeignKey(verbose_name=所属组,to="Group")

    class Meta:
        verbose_name_plural = "权限表"

    def __str__(self):
        return self.title

class User(models.Model):
    """
    用户表
    """
    username = models.CharField(verbose_name=用户名,max_length=32)
    password = models.CharField(verbose_name=密码,max_length=64)
    email = models.CharField(verbose_name=邮箱,max_length=32)

    roles = models.ManyToManyField(verbose_name=具有的所有角色,to="Role",blank=True)

    class Meta:
        verbose_name_plural = "用户表"

    def __str__(self):
        return self.username

class Role(models.Model):
    """
    角色表
    """
    title = models.CharField(max_length=32)
    permissions = models.ManyToManyField(verbose_name=具有的所有权限,to=Permission,blank=True)
    class Meta:
        verbose_name_plural = "角色表"

    def __str__(self):
        return self.title
models

2.- 初始化: 获取菜单信息+权限信息

技术分享
from django.conf import settings


def init_permission(user,request):
    """
    初始化权限信息,获取权限信息并放置到session中。
    :param user:
    :param request:
    :return:
    """
    permission_list = user.roles.values(permissions__title,              # 用户列表
                                        permissions__url,
                                        permissions__code,
                                        permissions__is_menu,            # 是否是菜单
                                        permissions__group_id,
                                        permissions__group__menu_id,     # 菜单ID
                                        permissions__group__menu__title,#  菜单名称
                                        ).distinct()

    menu_list = []
    # 去掉不是菜单的URL
    for item in permission_list:
        if not item[permissions__is_menu]:
            continue
        tpl = {
                menu_id:item[permissions__group__menu_id],
                menu_title:item[permissions__group__menu__title],
                title:item[permissions__title],
                url:item[permissions__url],
                active:False,
        }
        menu_list.append(tpl)

    request.session[settings.PERMISSION_MENU_KEY] = menu_list


    # 权限相关
    result = {}
    for item in  permission_list:
        group_id = item[permissions__group_id]
        code = item[permissions__code]
        url = item[permissions__url]
        if group_id in result:
            result[group_id][codes].append(code)
            result[group_id][urls].append(url)
        else:
            result[group_id] = {
                codes:[code,],
                urls:[url,]
            }

    request.session[settings.PERMISSION_URL_DICT_KEY] = result
init_permission.py

结构化数据 示例;

mport re
menu_list = [
    {menu_id:1, menu_title:菜单一,title:用户列表,url:/userinfo/,active:False},
    {menu_id:1, menu_title:菜单一,title:订单列表,url:/order/,active:False},
    {menu_id:2, menu_title:菜单二,title:xxx列表,url:/xxx/,active:False},
    {menu_id:2, menu_title:菜单二,title:iii列表,url:/uuu/,active:False},
]

current_url = "/userinfo/"

res={}

for tem in menu_list:
    mid=tem["menu_id"]
    mtitle=tem["menu_title"]
    title=tem["title"]
    url=tem["url"]
    active=False
    if re.match(url,current_url):
        active=True
    if mid in res:
        res[mid]["children"].append({"title":title,"url":url,"active":active})
        if active:
            res[mid]["active"]=True
    else:

        res[mid]={
            "menu_id":mid,
            "menu_title":mtitle,
            "active":active,
            "children":[
                {"title":title,"url":url,"active":True},

            ]
        }

print(res)

结果:

aa={
    1:
        {
            menu_id: 1,
            menu_title: 菜单一,
            active: True,
            children: [{title: 用户列表, url: /userinfo/, active: True},
                         {title: 订单列表, url: /order/, active: True}]
        },
    2:
        {
        menu_id: 2,
        menu_title: 菜单二,
        active: True,
        children: [{title: xxx列表, url: /xxx/, active: True},
                     {title: iii列表, url: /uuu/, active: True}]
       }
}

3.显示多级菜单

模块中操作
其中菜单部分由自定义标签生产
具体展示页面则用模块继承:如userinfo

a. base.html

{% load rbac %}
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
    <link rel="stylesheet" href="/static/rbac/rbac.css">
</head>
<body>
<div style="float: left;width: 20%;height: 900px;background-color: darkgrey">
  {% menu_html request %}
</div>
<div style="float: left;width: 80%">
   {% block content %}
    {% endblock %}
</div>
</body>
<script src="/static/jquery-3.2.1.min.js"></script>
<script src="/static/rbac/rbac.js"></script>
</html>

b. userinfo.html

{%  extends "base.html" %}
{% block content %}
{%   if pagepermission.has_add %}
<p><a href="">添加</a></p>
{% endif %}
<table>
    <thead>
    <th>id</th>
    <th>name</th>
    <th>操作</th>
    </thead>

    <tbody>
    {% for foo in data_list %}
      <tr>
      <td>{{ foo.id }}</td>
      <td>{{ foo.name }}</td>
      <td>
        {% if pagepermission.has_edit %}
            <a href="#">编辑</a>
        {% endif %}

      {% if pagepermission.has_del %}
          <a href="#">删除</a>
      {% endif %}
      </td>
      </tr>
    {% endfor %}

{% endblock %}

c.建立自定义标签

rbac/templatetags/rabc.py

技术分享
import re
from django.template import Library
from django.conf import settings
register = Library()

@register.inclusion_tag("menuList.html")
def menu_html(request):
    menu_list = request.session[settings.PERMISSION_MENU_KEY]
    current_url = request.path_info
    result = {}
    for item in menu_list:
        url = item[url]
        regex = "^{0}$".format(url)
        active = False
        if re.match(regex,current_url):
            active = True

        menu_id = item[menu_id]
        if menu_id in result:
            result[menu_id][children].append({title: item[title], url: item[url], active: active})
            if active:
                result[menu_id][active] = True
        else:
            result[menu_id] = {
                menu_id: menu_id,
                menu_title: item[menu_title],
                active: active,
                children: [
                    {title: item[title], url: item[url], active: active},
                ]
            }

    return {menu_dict:result}
rbac.py

d. menuList.html

{% for k,item in menu_dict.items %}
 <div class="item">
       <div class="item_title">{{ item.menu_title }}</div>
       {% if item.active %}
        <div class="item_permissions">
           {% else %}
           <div class="item_permissions hide">
       {% endif %}
          {% for v in item.children %}
           {% if v.active %}
               <a href="#" class="active">{{ v.title }}</a>
               {% else %}
               <a href="#">{{ v.title }}</a>
           {% endif %}
          {% endfor %}
       </div>
   </div>
{% endfor %}

e.相关css和js

在rbac建立static/rbac目录在其中创建rabc.css和rabc.js

技术分享
.item_permissions{
    padding: 3px 10px;
}

.item_permissions a{
    display: block;
}

.item_permissions a.active{
    color: red;
}

.hide{
    display: none;
}
rbac.css
技术分享
$(function () {
    $(".item_title").click(function () {
        $(this).next().toggleClass("hide")
    });
})
rbac.js

四.菜单展示改进

因为当我们对用户部分进行增删改时,用户列表也应该事展开的,但是我们上面所写的当我们点击增加删除编辑按钮时,用户菜单会闭合而不是展开的
对此我们进行了改进

1..在权限表中增加字段menu_gp,并删除is_menu字段

技术分享
from django.db import models

class Menu(models.Model):
    ‘‘‘
    菜单表
    ‘‘‘
    title=models.CharField(max_length=32,verbose_name="菜单名称")

class Group(models.Model):
    ‘‘‘
    权限组
    ‘‘‘
    caption=models.CharField(max_length=32,verbose_name="组名称")
    menu=models.ForeignKey(verbose_name="所属菜单",to="Menu",default=1)

class Permission(models.Model):
    """
    权限表
    """
    title = models.CharField(verbose_name=标题,max_length=32)
    url = models.CharField(verbose_name="含正则URL",max_length=64)
    # is_menu = models.BooleanField(verbose_name="是否是菜单")
    menu_gp=models.ForeignKey(verbose_name="组内菜单",to="Permission",null=True,blank=True)
    code=models.CharField(max_length=32,verbose_name="代码",default="list")
    group=models.ForeignKey(verbose_name="s所在权限组",to="Group",default=1)


    class Meta:
        verbose_name_plural = "权限表"

    def __str__(self):
        return self.title

class User(models.Model):
    """
    用户表
    """
    username = models.CharField(verbose_name=用户名,max_length=32)
    password = models.CharField(verbose_name=密码,max_length=64)
    email = models.CharField(verbose_name=邮箱,max_length=32)

    roles = models.ManyToManyField(verbose_name=具有的所有角色,to="Role",blank=True)

    class Meta:
        verbose_name_plural = "用户表"

    def __str__(self):
        return self.username

class Role(models.Model):
    """
    角色表
    """
    title = models.CharField(max_length=32)
    permissions = models.ManyToManyField(verbose_name=具有的所有权限,to=Permission,blank=True)
    class Meta:
        verbose_name_plural = "角色表"

    def __str__(self):
        return self.title
moedels.py

2.修改初始化中菜单

技术分享
from django.conf import settings
def init_permission(user,request):
    """
    初始化权限信息,获取权限信息并放置到session中。
    :param user:
    :param request:
    :return:
    """
    permission_list = user.roles.values(permissions__title,
                                        "permissions__code",
                                        "permissions__id",
                                        permissions__url,
                                        permissions__menu_gp_id,
                                        "permissions__group__id",
                                        "permissions__group__menu_id",
                                        "permissions__group__menu__title",
                                        ).distinct()



    menu_list=[]
    for item in permission_list:
        tpl={
            "id":item["permissions__id"],
            "title":item["permissions__title"],
            "menu_title":item["permissions__group__menu__title"],
            "url":item["permissions__url"],
            "menu_id":item["permissions__group__menu_id"],
            "menu_gp_id":item["permissions__menu_gp_id"],
        }
        menu_list.append(tpl)

    request.session[settings.PERMISSIONS_MENU_KEY]=menu_list



    # menu_list=[]
    # for item in permission_list:
    #     if not item["permissions__is_menu"]:
    #         continue
    #
    #     tpl={
    #         "menu_id":item["permissions__group__menu_id"],
    #         "menu_title":item["permissions__group__menu__title"],
    #         "title":item["permissions__title"],
    #         "url":item["permissions__url"],
    #         "active":False,
    #     }
    #
    #     menu_list.append(tpl)
    # print(menu_list)
    # request.session[settings.PERMISSIONS_MENU_KEY]=menu_list
     #权限管理
    result={}
    for item in permission_list:
        groupid=item["permissions__group__id"]
        code=item["permissions__code"]
        url=item["permissions__url"]

        if groupid in result:
            result[groupid]["codes"].append(code)
            result[groupid]["urls"].append(url)
        else:
            result[groupid]={
                "codes":[code,],
                "urls":[url,]
            }


    print(result)


    request.session[settings.PERMISSIONS_URL_DICT_KEY] = result
init_permission.py

3.修改定义标签

技术分享
import  re
from django.conf import settings
from django.template import Library
register = Library()
@register.inclusion_tag("menuList.html")
def menu_html(request):
    menu_list=request.session.get(settings.PERMISSIONS_MENU_KEY)
    currenturl=request.path_info


    menu_dict={}
    for item in menu_list:
        if not item["menu_gp_id"]:
            menu_dict[item["id"]]=item
    for item in menu_list:
        regex="^{0}$".format(item["url"])
        if re.match(regex,currenturl):
            menu_gp_id=item["menu_gp_id"]
            if not menu_gp_id:
                menu_dict[item["id"]]["active"]=True
            else:
                menu_dict[item["menu_gp_id"]]["active"]=True
    ‘‘‘
    menu_dict={
    1: {‘id‘: 1, ‘title‘: ‘用户列表‘, ‘url‘: ‘/userinfo/‘, ‘menu_gp_id‘: None, ‘menu_id‘: 1, ‘menu_title‘: ‘菜单管理‘, ‘active‘: True},
    5: {‘id‘: 5, ‘title‘: ‘订单列表‘, ‘url‘: ‘/order/‘, ‘menu_gp_id‘: None, ‘menu_id‘: 2, ‘menu_title‘: ‘菜单2‘}}
    ‘‘‘
    print(menu_dict,"11111111111111111111111111111111111111111111")
    result = {}
    for item in menu_dict.values():
        menu_id=item["menu_id"]
        menu_title=item["menu_title"]
        active=item.get("active")
        url=item["url"]
        title=item["title"]

        if menu_id in result:
            result[menu_id]["children"].append({"title":title,"url":url,"active":active})
            if active:
                result[menu_id]["active"]=True
        else:
            result[menu_id]={
                "menu_id":menu_id,
                "menu_title":menu_title,
                "active":active,
                "children":[
                    {"title":title,"url":url,"active":active},
                ]

            }

    print(result)

    # for item in menu_list:
    #     menu_id=item["menu_id"]
    #     menu_title=item["menu_title"]
    #     title=item["title"]
    #     url=item["url"]
    #     active=False
    #     regex="^{0}$".format(url)
    #     if re.match(regex,currenturl):
    #         active=True
    #
    #     if menu_id in result:
    #         result[menu_id]["children"].append({{"title":title,"url":url,"active":active},})
    #         if active:
    #             result[menu_id]["active"]=active
    #     else:
    #         result[menu_id]={
    #             "menu_id":menu_id,
    #             "menu_title":menu_title,
    #             "active":active,
    #             "children":[
    #                 {"title":title,"url":url,"active":active},
    #             ]
    #         }
    # print(result)
    return {"menu_dict":result}
rbac.py

其他不做修改

 

 

Django 权限管理

标签:any   12c   length   reg   settings   images   rmi   play   简单   

原文地址:http://www.cnblogs.com/ctztake/p/7812041.html

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