标签:style blog color io os java ar for 2014
题目:
The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return [0,1,3,2]
. Its
gray code sequence is:
00 - 0 01 - 1 11 - 3 10 - 2
Note:
For a given n, a gray code sequence is not uniquely defined.
For example, [0,2,3,1]
is also a valid gray code sequence according
to the above definition.
For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
思路:这是一道非常有意思的题。初看无下手之处,不过列举出前几项就很容易看出规律啦:
n = 1时:
0 (0)
1 (1)
n = 2时:
00 (0)
01 (1)
11 (3)
10 (2)
n = 3时:
000 (0)
001 (1)
011 (3)
010 (2)
110 (6)
111 (7)
101 (5)
100 (4)
可看出n每增加一位,结果数量翻倍,且前一半和n-1的结果是一样的,而后一半其实就是前半部分的镜像对称,再在最高位加上1.
所以完全可以用递归,通过n-1得到n的结果。代码如下:
public List<Integer> grayCode(int n) { List<Integer> result = new ArrayList<Integer>(); if(n<=1) { for(int i =0; i<=n; i++) { result.add(i); } return result; } result = grayCode(n-1); List<Integer> r1 = reverse(result); int x = 1<<(n-1); for(int i = 0; i< r1.size(); i++) { r1.set(i, r1.get(i)+x); } result.addAll(r1); return result; } public List<Integer> reverse(ArrayList<Integer> r) { List<Integer> result = new ArrayList<Integer>(); for(int i = r.size()-1; i>=0; i--) { result.add(r.get(i)); } return result; }
标签:style blog color io os java ar for 2014
原文地址:http://blog.csdn.net/he_wolf/article/details/39268455