[LeetCode] Self Dividing Numbers

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A self-dividing number is a number that is divisible by every digit it contains.

For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.

Also, a self-dividing number is not allowed to contain the digit zero.

Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.

Example 1:

Input: 
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]

Note:

• The boundaries of each input argument are 1 <= left <= right <= 10000.

找出给定区间内的自分数，自分数就是可以整除的数字中每一位数的那个数。由此判断自分数中不含有数字0。

首先写一个函数来判断自分数，按照自分数的定义书写即可。注意判断数字0不能是除数。

然后在主函数中，循环添加符合要求的自分数。

class Solution {
public:
    vector<int> selfDividingNumbers(int left, int right) {
        vector<int> res;
        for (int i = left; i <= right; i++) {
            if (isSelfDividingNumbers(i))
                res.push_back(i);
        }
        return res;
    }
    bool isSelfDividingNumbers(int num) {
        int tmp = num, digit = 0;
        while (tmp) {
            digit = tmp % 10;
            if (digit == 0 || num % digit != 0)
                return false;
            tmp /= 10;
        }
        return true;
    }
};
// 3 ms

[LeetCode] Self Dividing Numbers

标签：public   use   lock   possible   eve   including   return   style   函数   

原文地址：http://www.cnblogs.com/immjc/p/7865488.html