标签:title class col block nod des nbsp pre subject
题目描述
操作给定的二叉树,将其变换为源二叉树的镜像。输入描述:
二叉树的镜像定义:源二叉树 8 / 6 10 / \ / 5 7 9 11 镜像二叉树 8 / 10 6 / \ / 11 9 7 5
前序遍历交换儿子指针指向即可,要注意出现空的情况。
/* struct TreeNode { int val; struct TreeNode *left; struct TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) { } };*/ class Solution { public: void Mirror(TreeNode *pRoot) { if (!pRoot || !(pRoot->left) && !(pRoot->right)) return; TreeNode* tmp = pRoot->left; pRoot->left = pRoot->right; pRoot->right = tmp; Mirror(pRoot->left); Mirror(pRoot->right); } };
标签:title class col block nod des nbsp pre subject
原文地址:http://www.cnblogs.com/zmj97/p/7905249.html