标签:opera other printf pair can highlight queue str return
下载了一款推箱子小游戏,第13关的时候怎么也破不了最佳纪录(最少步数是9而我们最好的方案是10步),因为数据比较小(6*8的方阵),所以写了个BFS来找最短路。
游戏的目标是把小黄人推到黄色球,小绿人推到绿色球,有个限制是,小黄/绿人运动时会沿某一个方向一直走直到遇到边界或者障碍物,如果途中遇到传送带还会改变运动方向。
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每个状态转移的时候有4*2个选择。标记已经访问过的状态就好了。
#include <queue> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; typedef pair<int,int> Coord; struct Status{ Coord y,g; int step,fid,id; Status(const Coord& y,const Coord& g,int step=0):y(y),g(g),step(step){fid = -1; id = 0;} const Status& setId(int id,int fid){ this->id = id; this->fid = fid; return *this; } bool operator<(const Status& another) const { return step>another.step; } int hash(){ return y.first*1000+y.second*100+g.first*10+g.second; } friend ostream& operator<<(ostream& out,const Status& s){ return (out<<"yellow("<<s.y.first<<","<<s.y.second<<") green("<<s.g.first<<","<<s.g.second<<") step:"<<s.step); } }; Coord Y = {0,3}; Coord G = {5,2}; const int M = 6; const int N = 8; const int skip[4][2] = {{-1,0},{1,0},{0,1},{0,-1}}; bool vis[6868]; bool cango(int& x,int& y,int& dir,const Coord& another){ int tx = x + skip[dir][0]; int ty = y + skip[dir][1]; if(tx<0||ty<0||tx>=M||ty>=N) return false; if(tx==another.first&&ty==another.second) return false; x = tx,y = ty; if(x==3&&y==2) dir=1; if(x==4&&y==3) dir=0; return true; } bool mov(Coord &a,const Coord& b,int dir){ int len = 0; while(cango(a.first,a.second,dir,b)) len++; return len>0; } //for print path vector<Status> trace; void print(const Status& node){ if(node.fid==-1){ std::cout<<node<<endl; return ; } print(trace[node.fid]); std::cout<<node<<endl; } int main(){ Coord y = {0,5}; Coord g = {0,6}; Status start(y,g); memset(vis,false,sizeof(vis)); priority_queue<Status> q; q.push(start); vis[start.hash()] = true; trace.push_back(start); while(q.size()){ Status cur = q.top(); q.pop(); if(cur.g==G&&cur.y==Y){ printf("step: %d\n",cur.step); print(cur); break; } for(int i=0;i<4;i++){ Coord tmpy = cur.y; Coord tmpg = cur.g; if(mov(tmpy,cur.g,i)) { Status next(tmpy,cur.g,cur.step+1); if(!vis[next.hash()]){ trace.push_back(next.setId(trace.size(),cur.id)); q.push(next); vis[next.hash()]=true; } } if(mov(tmpg,cur.y,i)){ Status next(cur.y,tmpg,cur.step+1); if(!vis[next.hash()]){ trace.push_back(next.setId(trace.size(),cur.id)); q.push(next); vis[next.hash()]=true; } } } } return 0; }
标签:opera other printf pair can highlight queue str return
原文地址:http://www.cnblogs.com/redips-l/p/7909206.html