hx711测试11月28日调试

 1 #include <HX711.h> // 包含库的头文件
 2 #include <EEPROM.h>        //寄存器库
 3 #include <PinChangeInt.h>  
 4 long test;
 5 int i=0;
 6  HX711 hx(9, 10,64); // 数据接脚定义
 7  unsigned char *dpointer;
 8 union data {
 9   double v;
10   unsigned char dchar[8];
11 } dvalue;
12 ///////////////////////////////////////////////
13 long pyl (void)  //偏移量
14 {
15   pingjunzhi();
16   return pingjunzhi();
17   }
18 double  jiaozhun (void )
19 {
20  double jieguo1;
21  double jieguo2;
22  double jieguo3;
23  pingjunzhi();//空走一遍初始化校准程序
24 jieguo1=pingjunzhi();
25 Serial.println(jieguo1);
26 delay(1000); 
27 Serial.println("现在进行校准！请在3秒内放入500g砝码，请放入500g砝码"); 
28 delay(3000);
29  pingjunzhi();//空走一遍初始化校准程序
30  delay(1000);
31 jieguo2=pingjunzhi();
32 Serial.println(jieguo2); 
33 jieguo3=500/(jieguo2-jieguo1);
34 Serial.println("校准成功：修正系数为"); 
35 Serial.print(jieguo3,10); 
36 /////////////////////////////////////存储数据
37 dvalue.v =jieguo3;
38 dpointer = dvalue.dchar ;
39    for(i = 0; i < 8; i++) {
40       EEPROM.write(i,*dpointer);
41       dpointer++;
42     }
43     /////////////////////////////
44  Serial.println("误差系数记忆成功"); 
45   }
46 double pingjunzhi (void)
47 {
48 double zhi;
49 double sum = 0;    // 为了减小误差，一次取出10个值后求平均值。
50 for (int i = 0; i < 10; i++) // 循环的越多精度越高，当然耗费的时间也越多
51 sum += hx.read();  // 累加
52 zhi=sum/10;
53 //Serial.println(zhi); // 求平均值进行均差
54 return zhi;   
55   }
56 double jiance (void)
57 {
58     Serial.println("开机检测设备，，，，，，，"); 
59     delay(3000);
60 if(digitalRead(4) ==HIGH) 
61 jiaozhun ();
62 
63      delay(500);
64      for(i = 0; i < 8; i++) dvalue.dchar[i] = EEPROM.read(i);
65   Serial.println("误差系数记忆值为");   
66  Serial.print(dvalue.v,10); 
67  delay(500);
68  Serial.println("即将进入称量状态"); 
69   return dvalue.v;
70   }
71 void setup() {
72  Serial.begin(9600);
73  long y =pyl();
74  Serial.println(pyl());   
75  double x = jiance();
76   Serial.println(x); 
77  hx.set_co(x); //修改修正系数
78  hx.set_offset(y);//修改偏移值
79  delay(5000); 
80 }
81 void loop()
82 {
83    delay(1000);
84   double sum0 = 0;
85   double sum1 = 0;
86   for (int i = 0; i < 10; i++) {
87     sum0 += hx.read();
88     sum1 += hx.bias_read();
89   }
90   Serial.print(sum0/10);
91   Serial.print(" ");
92   Serial.println(sum1/10);
93 }