标签:hdu 数学
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1708
Problem Description
After little Jim learned Fibonacci Number in the class , he was very interest in it.
Now he is thinking about a new thing -- Fibonacci String .
He defines : str[n] = str[n-1] + str[n-2] ( n > 1 )
He is so crazying that if someone gives him two strings str[0] and str[1], he will calculate the str[2],str[3],str[4] , str[5]....
For example :
If str[0] = "ab"; str[1] = "bc";
he will get the result , str[2]="abbc", str[3]="bcabbc" , str[4]="abbcbcabbc" …………;
As the string is too long ,Jim can‘t write down all the strings in paper. So he just want to know how many times each letter appears in Kth Fibonacci String . Can you help him ?
Input
The first line contains a integer N which indicates the number of test cases.
Then N cases follow.
In each case,there are two strings str[0], str[1] and a integer K (0 <= K < 50) which are separated by a blank.
The string in the input will only contains less than 30 low-case letters.
Output
For each case,you should count how many times each letter appears in the Kth Fibonacci String and print out them in the format "X:N".
If you still have some questions, look the sample output carefully.
Please output a blank line after each test case.
To make the problem easier, you can assume the result will in the range of int.
Sample Input
Sample Output
a:1
b:3
c:2
d:0
e:0
f:0
g:0
h:0
i:0
j:0
k:0
l:0
m:0
n:0
o:0
p:0
q:0
r:0
s:0
t:0
u:0
v:0
w:0
x:0
y:0
z:0
Author
linle
Source
PS:
记录斐波那契的数组当时傻逼了也开成了26,导致WA了几把都找不到原因!
图样图森破!
代码如下:
#include <cstdio>
#include <cstring>
int main()
{
int t;
char s0[30], s1[30];
int k, a0[26], a1[26];
int c[50];
c[0] = 0, c[1] = 1;
for(int i = 2; i <= 50; i++)
{
c[i] = c[i-1] + c[i-2];
}
scanf("%d",&t);
while(t--)
{
memset(s0,0,sizeof(s0));
memset(s1,0,sizeof(s1));
memset(a0,0,sizeof(a0));
memset(a1,0,sizeof(a1));
scanf("%s%s%d",s0,s1,&k);
for(int i = 0; i < strlen(s0); i++)
{
int tt = s0[i]-'a';
a0[tt]++;
}
for(int i = 0; i < strlen(s1); i++)
{
int tt = s1[i]-'a';
a1[tt]++;
}
for(int i = 0; i < 26; i++)
{
if(k == 0)
{
printf("%c:%d\n",'a'+i,a0[i]);
}
else
printf("%c:%d\n",'a'+i,a0[i]*c[k-1]+a1[i]*c[k]);
}
printf("\n");
}
return 0;
}
HDU 1708 Fibonacci String(数学题)
标签:hdu 数学
原文地址:http://blog.csdn.net/u012860063/article/details/39298029