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Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
题意:求给定的一棵二叉树的最大深度
思路:dfs递归。树的最大深度=max(左子树的最大深度,右子树的最大深度) + 1
复杂度:时间O(n)(因为每个节点都要访问一次),空间O(log n)(因为递归压栈要保存root指针,栈最大为log n)
相关题目: Minimum Depth of Binary Tree
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int maxDepth(TreeNode *root) { if(root == NULL) return 0; return max(maxDepth(root->left) , maxDepth(root->right)) + 1; } };
Leetcode 树 Maximum Depth of Binary Tree,布布扣,bubuko.com
Leetcode 树 Maximum Depth of Binary Tree
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原文地址:http://blog.csdn.net/zhengsenlie/article/details/25510313