标签:ransient 将不 pes types byte [] getname 一个 ack
在看java.util.ArrayList这个类的源码时,发现其中有个成员变量Object[] elementData 被transient修饰了。突然脑袋回忆不起这个关键字的具体用法了,只知道被此关键字修饰的成员变量不会被序列化。于是我查阅了一下资料。
当一个类实现了Serializable接口后,那么他就是可被序列化的。一个继承了可序列化类的类本身也是可别序列化的。(源码描述:
Serializability of a class is enabled by the class implementing the java.io.Serializable interface. All subtypes of a serializable class are themselves serializable.
)
在一个可被序列化的类中:
1.transient只能修饰成员变量/类变量,被它修饰的成员变量将不能被序列化(类变量无论是否被transient修饰都无法被序列化)
2.如果成员变量是自定义对象类型,那么也必须是可序列化的。如果不是,则可以通过transient修饰,否则会报java.io.NotSerializableException异常。
测试:
1 package com.test; 2 import java.io.*; 3 public class TestTransient { 4 5 public static void main(String[] args) throws IOException, ClassNotFoundException { 6 User user = new User(); 7 user.setPassword("password"); 8 user.setUsername("jery"); 9 person p = new person(); 10 p.setName("tom"); 11 p.setAge(12); 12 user.setPerson(p); 13 14 ByteArrayOutputStream bos = new ByteArrayOutputStream(); 15 ObjectOutputStream os = new ObjectOutputStream(bos); 16 os.writeObject(user); 17 // user.setUsername("yiiiy"); 测试username被static修饰后,是否会被序列化 18 byte[] bytes = bos.toByteArray(); 19 ObjectInputStream is = new ObjectInputStream(new ByteArrayInputStream(bytes)); 20 User u = (User) is.readObject(); 21 System.out.println(u); 22 } 23 } 24 25 class User implements Serializable{ 26 private String username; 27 private String password; 28 transient person person; 29 30 public com.common.util.person getPerson() { 31 return person; 32 } 33 34 public void setPerson(com.common.util.person person) { 35 this.person = person; 36 } 37 38 public String getUsername() { 39 return username; 40 } 41 42 public void setUsername(String username) { 43 this.username = username; 44 } 45 46 public String getPassword() { 47 return password; 48 } 49 50 public void setPassword(String password) { 51 this.password = password; 52 } 53 54 @Override 55 public String toString() { 56 return "User{" + 57 "username=‘" + username + ‘\‘‘ + 58 ", password=‘" + password + ‘\‘‘ + 59 ", person=" + person + 60 ‘}‘; 61 } 62 } 63 64 class person{ 65 private String name; 66 private Integer age; 67 68 public String getName() { 69 return name; 70 } 71 72 public void setName(String name) { 73 this.name = name; 74 } 75 76 public Integer getAge() { 77 return age; 78 } 79 80 @Override 81 public String toString() { 82 return "person{" + 83 "name=‘" + name + ‘\‘‘ + 84 ", age=" + age + 85 ‘}‘; 86 } 87 88 public void setAge(Integer age) { 89 this.age = age; 90 } 91 }
标签:ransient 将不 pes types byte [] getname 一个 ack
原文地址:http://www.cnblogs.com/tljava/p/8016672.html