""" @href: https://leetcode.com/problems/wildcard-matching/description/ @title: 44. Wildcard Matching """ class Solution(object): def isMatch(self, s, p): """ :type s: str :type p: str :rtype: bool """ ls, lp = len(s), len(p) if (ls + lp) == 0: return True s, p = ‘a‘ + s, ‘a‘ + p ls, lp = ls+1, lp+1 dp = [[False]*(lp+1) for i in range(0, ls+1)] dp[0][0] = True for i in range(1, ls+1): for j in range(1, lp+1): if p[j-1] == s[i-1] or p[j-1] in ‘?*‘: dp[i][j] = dp[i-1][j-1] if p[j-1] == ‘*‘: dp[i][j] = dp[i][j] or dp[i-1][j] or dp[i][j-1] else: if p[j-1] == ‘*‘: dp[i][j] = dp[i][j-1] return dp[ls][lp]
我用的是二维 dp, 有人给出了 一维 dp 解法