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HDU_oj_2055 An easy problem

时间:2017-12-17 14:16:44      阅读:184      评论:0      收藏:0      [点我收藏+]

标签:bottom   esc   size   res   sam   ios   16px   line   contains   

Problem Description
 
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
 
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
 
Output
for each case, you should the result of y+f(x) on a line.
 
Sample Input
6
1
2
3
1
p 2
g 3
 
Sample
Output
19
18
10
-17
-14
-4
 
分析:无
注意点:无
 1 #include<iostream>
 2 using namespace std;
 3 
 4 int main()
 5 {
 6     char c;
 7     int  d;
 8     int  n;
 9     while(cin>>n)
10     {
11         while(n--)
12         {
13             cin>>c>>d;
14             if(c>64&&c<92)
15             d=d+c-64;
16             else 
17             d=d+(c-96)*(-1);
18             cout<<d<<endl;
19         }
20     }
21 }

 

 

 

HDU_oj_2055 An easy problem

标签:bottom   esc   size   res   sam   ios   16px   line   contains   

原文地址:http://www.cnblogs.com/tenjl-exv/p/8051799.html

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