码迷,mamicode.com
首页 > 其他好文 > 详细

Topological Sor-207. Course Schedule

时间:2018-01-13 11:08:13      阅读:178      评论:0      收藏:0      [点我收藏+]

标签:code   computer   span   www   duplicate   sse   ges   targe   ted   

There are a total of n courses you have to take, labeled from 0 to n - 1.

Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]

Given the total number of courses and a list of prerequisite pairs, is it possible for you to finish all courses?

For example:

2, [[1,0]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible.

2, [[1,0],[0,1]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.

Note:

  1. The input prerequisites is a graph represented by a list of edges, not adjacency matrices. Read more about how a graph is represented.
  2. You may assume that there are no duplicate edges in the input prerequisites.
class Solution {
public:
    bool canFinish(int numCourses, vector<pair<int, int>>& prerequisites) {
        vector<vector<int>> graph(numCourses, vector<int>(0)); 
        vector<int> in(numCourses, 0); 
        for (auto a : prerequisites) { 
            graph[a.second].push_back(a.first);
            ++in[a.first];
        }
        queue<int> q; 
        for (int i = 0; i < numCourses; ++i) {
            if (in[i] == 0) q.push(i);
        }
        while (!q.empty()) {
            int t = q.front();
            q.pop();
            for (auto a : graph[t]) {
                --in[a];
                if (in[a] == 0) q.push(a);
            }
        }
        for (int i = 0; i < numCourses; ++i) {
            if (in[i] != 0) return false;
        }
        return true;
    }
};

 

Topological Sor-207. Course Schedule

标签:code   computer   span   www   duplicate   sse   ges   targe   ted   

原文地址:https://www.cnblogs.com/msymm/p/8278253.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!