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[leetcode]Tree-669. Trim a Binary Search Tree

时间:2018-01-13 20:44:40      阅读:134      评论:0      收藏:0      [点我收藏+]

标签:hang   bsp   bin   ==   sea   inpu   arc   should   binary   

Given a binary search tree and the lowest and highest boundaries as L and R, trim the tree so that all its elements lies in [L, R] (R >= L). You might need to change the root of the tree, so the result should return the new root of the trimmed binary search tree.

Example 1:

Input: 
    1
   /   0   2

  L = 1
  R = 2

Output: 
    1
             2

 

Example 2:

Input: 
    3
   /   0   4
       2
   /
  1

  L = 1
  R = 3

Output: 
      3
     / 
   2   
  /
 1
class Solution {  
public:  
    TreeNode* trimBST(TreeNode* root, int L, int R) {  
        if (root == nullptr)  
            return 0;  
        if (root->val < L)  
            return trimBST(root->right, L, R);  
        else if (root->val > R)   
            return trimBST(root->left, L, R);  
        else {  
            root->left = trimBST(root->left, L, R);  
            root->right = trimBST(root->right, L, R);  
            return root;  
        }  
    }  
};  

 

[leetcode]Tree-669. Trim a Binary Search Tree

标签:hang   bsp   bin   ==   sea   inpu   arc   should   binary   

原文地址:https://www.cnblogs.com/chenhan05/p/8280196.html

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