# [leetcode]Array-697. Degree of an Array

Given a non-empty array of non-negative integers `nums`, the degree of this array is defined as the maximum frequency of any one of its elements.

Your task is to find the smallest possible length of a (contiguous) subarray of `nums`, that has the same degree as `nums`.

Example 1:

```Input: [1, 2, 2, 3, 1]
Output: 2
Explanation:
The input array has a degree of 2 because both elements 1 and 2 appear twice.
Of the subarrays that have the same degree:
[1, 2, 2, 3, 1], [1, 2, 2, 3], [2, 2, 3, 1], [1, 2, 2], [2, 2, 3], [2, 2]
The shortest length is 2. So return 2.
```

Example 2:

```Input: [1,2,2,3,1,4,2]
Output: 6```
```class Solution {
2 public:
3     int findShortestSubArray(vector<int>& nums) {
4         int len = nums.size() ;
5         if (len < 2)
6             return len ;
7         int Max = 0 ;
8         unordered_map<int,int> startIndex , count ;
9         int res = len ;
10         for(int i = 0 ; i < len ; i++){
11             if (startIndex.count(nums[i]) == 0)
12                 startIndex[nums[i]] = i ;
13             count[nums[i]]++ ;
14             if (count[nums[i]] > Max){
15                 res = i - startIndex[nums[i]] + 1 ;
16                 Max = count[nums[i]] ;
17             }
18             if (count[nums[i]] == Max){
19                 res = min(i - startIndex[nums[i]] + 1 , res) ;
20             }
21         }
22         return res ;
23     }
24 };  ```

[leetcode]Array-697. Degree of an Array

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