标签:des style blog http color io os java ar
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4093 Accepted Submission(s): 2933
Mean:
略
analyse:
经典的母函数运用题。
Time complexity:O(n^3)
Source code:
// Memory Time // 1347K 0MS // by : Snarl_jsb // 2014-09-18-13.40 #include<algorithm> #include<cstdio> #include<cstring> #include<cstdlib> #include<iostream> #include<vector> #include<queue> #include<stack> #include<map> #include<string> #include<climits> #include<cmath> #define N 1000010 #define LL long long using namespace std; int cnt[100],c1[100],c2[100]; int main() { ios_base::sync_with_stdio(false); cin.tie(0); // freopen("C:\\Users\\ASUS\\Desktop\\cin.cpp","r",stdin); // freopen("C:\\Users\\ASUS\\Desktop\\cout.cpp","w",stdout); int Cas; cin>>Cas; while(Cas--) { for(int i=1;i<=26;++i) cin>>cnt[i]; memset(c1,0,sizeof(c1)); //以防后面越界,最好全部赋值为0 memset(c2,0,sizeof(c2)); for(int i=0;i<=cnt[1]&&i<=50;++i) c1[i]=1; for(int i=2;i<=26;++i) { for(int j=0;j<=50;++j) { for(int k=0;k+j<=50&&k<=cnt[i]*i;k+=i) { c2[k+j]+=c1[j]; } } for(int j=0;j<=50;++j) { c1[j]=c2[j]; c2[j]=0; } } long long ans=0; for(int i=1;i<=50 ;++i) ans+=c1[i]; cout<<ans<<endl; } return 0; }
组合数学 - 母函数的运用 + 模板 --- hdu : 2082
标签:des style blog http color io os java ar
原文地址:http://www.cnblogs.com/acmer-jsb/p/3979112.html