Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123
Output: 321
Example 2:
Input: -123
Output: -321
Example 3:
Input: 120
Output: 21
Note:
Assume we are dealing with an environment which could only hold integers within the 32-bit signed integer range. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
反转一个整数,溢出时返回0
C++(26ms):
1 class Solution { 2 public: 3 int reverse(int x) { 4 long long res = 0 ; 5 while(x){ 6 res = res*10 + x%10 ; 7 x /= 10 ; 8 } 9 if (res < INT_MIN || res > INT_MAX) 10 return 0 ; 11 else 12 return res ; 13 } 14 };