标签:des style blog color io os java ar strong
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 13129 Accepted Submission(s): 9285
Mean:
给你一个n,问你n的拆分有多少种。
analyse:
经典的母函数运用题,不解释。
Time complexity:O(n^3)
Source code:
// Memory Time // 1347K 0MS // by : Snarl_jsb // 2014-09-18-15.21 #include<algorithm> #include<cstdio> #include<cstring> #include<cstdlib> #include<iostream> #include<vector> #include<queue> #include<stack> #include<map> #include<string> #include<climits> #include<cmath> #define N 1000010 #define LL long long using namespace std; int c1[300],c2[300]; int main() { ios_base::sync_with_stdio(false); cin.tie(0); // freopen("C:\\Users\\ASUS\\Desktop\\cin.cpp","r",stdin); // freopen("C:\\Users\\ASUS\\Desktop\\cout.cpp","w",stdout); int n; while(cin>>n) { memset(c1,0,sizeof(c1)); memset(c2,0,sizeof(c2)); for(int i=0;i<=n;++i) { c1[i]=1; } for(int i=2;i<=n;i++) { for(int j=0;j<=n;++j) { for(int k=0;k<=n;k+=i) { c2[k+j]+=c1[j]; } } for(int j=0;j<=n;++j) { c1[j]=c2[j]; c2[j]=0; } } cout<<c1[n]<<endl; } return 0; }
标签:des style blog color io os java ar strong
原文地址:http://www.cnblogs.com/acmer-jsb/p/3979326.html