A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.
Now given an M x N matrix, return True if and only if the matrix is Toeplitz.
Example 1:
Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]] Output: True Explanation: 1234 5123 9512 In the above grid, the diagonals are "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]", and in each diagonal all elements are the same, so the answer is True.
Example 2:
Input: matrix = [[1,2],[2,2]] Output: False Explanation: The diagonal "[1, 2]" has different elements.
Note:
matrixwill be a 2D array of integers.matrixwill have a number of rows and columns in range[1, 20].matrix[i][j]will be integers in range[0, 99].
class Solution:def isToeplitzMatrix(self, matrix):""":type matrix: List[List[int]]:rtype: bool"""if not matrix or not matrix[0]:return FalserowNum = max(0, len(matrix) - 1)colNum = max(0, len(matrix[0]) - 1)if rowNum is 0 or colNum is 0:return Truefor i in range(rowNum):for j in range(colNum):if matrix[i][j] != matrix[i + 1][j + 1]:return Falsereturn True# matrix = [# [1, 2, 3, 4],# [5, 1, 2, 3],# [9, 5, 1, 2]# ]# matrix = [# [1, 2],# [2, 2]# ]matrix = [[39, 24],[24, 39],[65, 24]]#matrix = [[10], [11], [12]]s = Solution()res = s.isToeplitzMatrix(matrix)print(res)
