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[LeetCode] Min Cost Climbing Stairs 爬楼梯的最小损失

时间:2018-01-25 00:26:19      阅读:165      评论:0      收藏:0      [点我收藏+]

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On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed).

Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step with index 0, or the step with index 1.

Example 1:

Input: cost = [10, 15, 20]
Output: 15
Explanation: Cheapest is start on cost[1], pay that cost and go to the top.

 

Example 2:

Input: cost = [1, 100, 1, 1, 1, 100, 1, 1, 100, 1]
Output: 6
Explanation: Cheapest is start on cost[0], and only step on 1s, skipping cost[3].

 

Note:

  1. cost will have a length in the range [2, 1000].
  2. Every cost[i] will be an integer in the range [0, 999].

 

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[LeetCode] Min Cost Climbing Stairs 爬楼梯的最小损失

标签:tco   esc   exe   tput   length   int   sig   from   and   

原文地址:https://www.cnblogs.com/grandyang/p/8343874.html

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