本文地址: http://blog.csdn.net/caroline_wendy
排序分割, 把一个数组分为, 大于k\小于k\等于k的三个部分.
可以使用快速排序的Partition函数, 进行处理, 把大于k的放在左边, 小于k的放在右边.
使用一个变量记录中间的位置, 则时间复杂度为O(3n/2).
代码:
/* * main.cpp * * Created on: 2014.9.18 * Author: Spike */ /*eclipse cdt, gcc 4.8.1*/ #include <iostream> #include <list> #include <queue> #include <string.h> #include <stdlib.h> using namespace std; int RandomInRange(int min, int max) { return rand()%(max-min+1) + min; } void Swap(int* num1, int* num2) { int tmp = *num1; *num1 = *num2; *num2 = tmp; } int PartitionK (int data[], int length, int k) { if (data == NULL || length <= 0) return -1; int small = -1; int index = 0; for (index=0; index<length; ++index) { if (data[index] < k) { small++; if (small != index) Swap(&data[small], &data[index]); } } int pos = ++small; //记录位置 small = length; index = 0; for (index = length-1; index>=pos; index--) { if (data[index] > k) { small--; if (small != index) Swap(&data[small], &data[index]); } } return --small; } int main (void) { int data[] = {1, 3, 2, 5, 2, 0, 5, 2, -1, 0, 4}; int length = sizeof(data)/sizeof(data[0]); PartitionK(data, length, 2); for (int i=0; i<length; ++i) { cout << data[i] << " "; } cout << endl; return 0; }
1 0 -1 0 2 2 2 3 5 5 4
原文地址:http://blog.csdn.net/caroline_wendy/article/details/39378187