题目：给你一个整数n. 从 1 到 n 按照下面的规则打印每个数：
- 如果这个数被3整除，打印
fizz. - 如果这个数被5整除，打印
buzz. - 如果这个数能同时被
3和5整除，打印fizz buzz.
样例
比如 n = 15, 返回一个字符串数组：
[ "1", "2", "fizz", "4", "buzz", "fizz", "7", "8", "fizz", "buzz", "11", "fizz", "13", "14", "fizz buzz" ]
Can you do it with only one if statement?
解：简单的if判断
class Solution { public: /* * @param n: An integer * @return: A list of strings. */ vector<string> fizzBuzz(int n) { // write your code here vector<string> re; for(int i=1;i<=n;i++) { if(i%3==0&&i%5!=0) { re.push_back("fizz"); }else if(i%3!=0&&i%5==0) { re.push_back("buzz"); }else if(i%3==0) { re.push_back("fizz buzz"); }else re.push_back(to_string(i)); } return re; } };
