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CF467 AB 水题

时间:2014-09-19 08:47:25      阅读:239      评论:0      收藏:0      [点我收藏+]

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Codeforces Round #267 (Div. 2)

(C和D的题解单独写:CF467C George and Job (DP) CF467D Fedor and Essay 建图DFS

 

CF#267A

CF#267B

A

 

题意:给出宿舍各个寝室住了多少人、最多能住多少人,求有多少个寝室能住进这两个人……

代码:

bubuko.com,布布扣
 1 //#pragma comment(linker, "/STACK:102400000,102400000")
 2 #include<cstdio>
 3 #include<cmath>
 4 #include<iostream>
 5 #include<cstring>
 6 #include<algorithm>
 7 #include<cmath>
 8 #include<map>
 9 #include<set>
10 #include<stack>
11 #include<queue>
12 using namespace std;
13 #define ll long long
14 #define usll unsigned ll
15 #define mz(array) memset(array, 0, sizeof(array))
16 #define minf(array) memset(array, 0x3f, sizeof(array))
17 #define REP(i,n) for(i=0;i<(n);i++)
18 #define FOR(i,x,n) for(i=(x);i<=(n);i++)
19 #define RD(x) scanf("%d",&x)
20 #define RD2(x,y) scanf("%d%d",&x,&y)
21 #define RD3(x,y,z) scanf("%d%d%d",&x,&y,&z)
22 #define WN(x) printf("%d\n",x);
23 #define RE  freopen("D.in","r",stdin)
24 #define WE  freopen("1biao.out","w",stdout)
25 #define mp make_pair
26 #define pb push_back
27 const double eps=1e-10;
28 const double pi=acos(-1.0);
29 
30 int main(){
31     int n,x,y,ans=0;
32     RD(n);
33     while(n--){
34         RD2(x,y);
35         if(y-x>=2)ans++;
36     }
37     WN(ans);
38     return 0;
39 }
View Code

 

 

 

B

 

题意:给出n,m,k,给出m+1个数a[i],代表m+1个人的那个什么情况,主角是第m+1个人。求a[i]和a[m+1]的n个二进制位中,有不超过k位不同的i有多少个(1<=i<=m)。

题解:直接暴力搞啊

代码:

bubuko.com,布布扣
 1 //#pragma comment(linker, "/STACK:102400000,102400000")
 2 #include<cstdio>
 3 #include<cmath>
 4 #include<iostream>
 5 #include<cstring>
 6 #include<algorithm>
 7 #include<cmath>
 8 #include<map>
 9 #include<set>
10 #include<stack>
11 #include<queue>
12 using namespace std;
13 #define ll long long
14 #define usll unsigned ll
15 #define mz(array) memset(array, 0, sizeof(array))
16 #define minf(array) memset(array, 0x3f, sizeof(array))
17 #define REP(i,n) for(i=0;i<(n);i++)
18 #define FOR(i,x,n) for(i=(x);i<=(n);i++)
19 #define RD(x) scanf("%d",&x)
20 #define RD2(x,y) scanf("%d%d",&x,&y)
21 #define RD3(x,y,z) scanf("%d%d%d",&x,&y,&z)
22 #define WN(x) printf("%d\n",x);
23 #define RE  freopen("D.in","r",stdin)
24 #define WE  freopen("1biao.out","w",stdout)
25 #define mp make_pair
26 #define pb push_back
27 const double eps=1e-10;
28 const double pi=acos(-1.0);
29 int a[1111];
30 int n,m,k;
31 int main(){
32     int i,j;
33     RD3(n,m,k);
34     REP(i,m+1){
35         RD(a[i]);
36     }
37     int q=a[m];
38     int ans=0;
39     REP(i,m){
40         int t=q^a[i];
41         int dif=0;
42         REP(j,n){
43             if((t&1)==1)dif++;
44             t>>=1;
45         }
46         if(dif<=k)ans++;
47     }
48     WN(ans);
49     return 0;
50 }
View Code

 

CF467 AB 水题

标签:style   blog   http   color   io   os   ar   strong   for   

原文地址:http://www.cnblogs.com/yuiffy/p/3980601.html

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