矩阵加速floyd……牛逼牛逼。
注意离散化,注意更新的时候要用旧的权值矩阵更新。
#include<cstdio> #include<cstring> #include<cctype> #include<cstdlib> #include<algorithm> #define maxn 300 #define check(x) if(x==0) x=++size; using namespace std; inline long long read(){ long long num=0,f=1; char ch=getchar(); while(!isdigit(ch)){ if(ch==‘-‘) f=-1; ch=getchar(); } while(isdigit(ch)){ num=num*10+ch-‘0‘; ch=getchar(); } return num*f; } int size,n; struct Matrix{ long long s[maxn][maxn]; void clear(){memset(s,127/3,sizeof(s));} Matrix operator *(const Matrix x){ Matrix ans; for(int k=1;k<=size;++k) for(int i=1;i<=size;++i) for(int j=1;j<=size;++j) ans.s[i][j]=min(ans.s[i][j],s[i][k]+x.s[k][j]); return ans; } }; Matrix Pow(Matrix now,int x){ Matrix ret; memset(ret.s,0,sizeof(ret.s)); for(int i=1;i<=size;++i) ret.s[i][i]=1; while(x){ if(x&1) ret=ret*now; now=now*now; x>>=1; } return ret; } int id[maxn*4]; int main(){ int m=read(),e=read(),Start=read(),End=read(); Matrix ret;ret.clear(); for(int i=1;i<=n;++i){ int len=read(),x=read(),y=read(); check(id[x]); check(id[y]); ret.s[id[x]][id[y]]=len; } ret=Pow(ret,m); printf("%d",ret.s[id[Start]][id[End]]); return 0; }