leetcode - Binary Tree Postorder Traversal

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Given a binary tree, return the postorder traversal of its nodes‘ values.

For example:
Given binary tree {1,#,2,3},

   1
         2
    /
   3

return [3,2,1].

Note: Recursive solution is trivial, could you do it iteratively?

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */

//BinTree的后序遍历
struct TreeNode
{
	int val;
	TreeNode *left;
	TreeNode *right;
	TreeNode(int x) : val(x),left(NULL),right(NULL) {}
};
class Solution {
public:
	std::vector<int> postorderTraversal(TreeNode *root) {
		std::vector<int> vec;
		BinTree(root,vec);
		return vec;
    }
	void BinTree(TreeNode *root,std::vector<int> &vec)
	{
		if(root != NULL)
		{
			BinTree(root->left,vec);
			BinTree(root->right,vec);
			vec.push_back(root->val);
		}
	}
private:
	std::vector<int> vec;
};

leetcode - Binary Tree Postorder Traversal

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原文地址：http://blog.csdn.net/akibatakuya/article/details/39400099