The new operating system BerOS has a nice feature. It is possible to use any number of characters ‘/‘ as a delimiter in path instead of one traditional ‘/‘. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character ‘/‘ (or some sequence of such characters) at the end of the path is required only in case of the path to the root directory, which can be represented as single character ‘/‘.
A path called normalized if it contains the smallest possible number of characters ‘/‘.
Your task is to transform a given path to the normalized form.
The first line of the input contains only lowercase Latin letters and character ‘/‘ — the path to some directory. All paths start with at least one character ‘/‘. The length of the given line is no more than 100 characters, it is not empty.
The path in normalized form.
//usr///local//nginx/sbin
/usr/local/nginx/sbin
读懂题意就好，英语不好。
代码：
#include <iostream> #include <cstring> #include <cstdio> #include <queue> #include <algorithm> #include <cmath> using namespace std; int main() { char s[105]; char t[105]; scanf("%s",s); int i = 0,j = 0,c = 0; while(s[i]) { t[j ++] = s[i]; if(s[i] == ‘/‘) { c ++; while(s[i + 1] == ‘/‘)i ++; } i ++; } if(c > 1)while(t[j - 1] == ‘/‘)j --; t[j] = ‘\0‘; printf("%s",t); }
