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LeetCode:Search for a Range

时间:2014-09-21 19:36:11      阅读:172      评论:0      收藏:0      [点我收藏+]

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Given a sorted array of integers, find the starting and ending position of a given target value.

Your algorithm‘s runtime complexity must be in the order of O(log n).

If the target is not found in the array, return [-1, -1].

For example,
Given [5, 7, 7, 8, 8, 10] and target value 8,
return [3, 4].

 

 1 class Solution {
 2 public:
 3     vector<int> searchRange(int A[], int n, int target) {
 4         vector<int> res={-1,-1};
 5         for(int i=0;i<n;i++)
 6         {
 7             if(target==A[i])
 8             {
 9                 res[0]=i;
10                 while(i+1<n&&target==A[i+1])
11                     i++;
12                 res[1]=i;
13                 break;
14             }
15         }
16         return res;
17     }
18 };

 

LeetCode:Search for a Range

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原文地址:http://www.cnblogs.com/levicode/p/3984705.html

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