ZOJ - 1108 输出DP方案

#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cmath>
#include<string>
#include<vector>
#include<stack>
#include<queue>
#include<set>
#include<map>
#define rep(i,j,k) for(register int i=j;i<=k;i++)
#define rrep(i,j,k) for(register int i=j;i>=k;i--)
#define erep(i,u) for(register int i=head[u];~i;i=nxt[i])
#define iin(a) scanf("%d",&a)
#define lin(a) scanf("%lld",&a)
#define din(a) scanf("%lf",&a)
#define s0(a) scanf("%s",a)
#define s1(a) scanf("%s",a+1)
#define print(a) printf("%lld",(ll)a)
#define enter putchar(‘\n‘)
#define blank putchar(‘ ‘)
#define println(a) printf("%lld\n",(ll)a)
#define IOS ios::sync_with_stdio(0)
using namespace std;
const int maxn = 1e4+11;
const int oo = 0x3f3f3f3f;
const double eps = 1e-7;
typedef long long ll;
ll read(){
    ll x=0,f=1;register char ch=getchar();
    while(ch<‘0‘||ch>‘9‘){if(ch==‘-‘)f=-1;ch=getchar();}
    while(ch>=‘0‘&&ch<=‘9‘){x=x*10+ch-‘0‘;ch=getchar();}
    return x*f;
}
int n,dp[maxn],pre[maxn],aa,bb;
struct A{
    int fat,speed,pos;
}a[maxn];
bool cmp(A a,A b){
    return a.fat<b.fat;
}
int main(){
    while(cin>>aa>>bb){
        a[++n].fat=aa;
        a[n].speed=bb;
        a[n].pos=n;
    }
    sort(a+1,a+1+n,cmp);
    rep(i,1,n) dp[i]=1;
    rep(i,1,n){
        rep(j,1,i-1){
            if(a[i].fat>a[j].fat&&a[i].speed<a[j].speed){
                if(dp[i]<dp[j]+1){
                    dp[i]=dp[j]+1;
                    pre[i]=j;
                }
            }
        }
    }
    ll ans=1,st=1;
    rrep(i,n,1) if(dp[i]>ans){
        ans=dp[i];
        st=i;
    }
    println(ans);
    stack<int> stk;
    while(st){
        stk.push(st);
        st=pre[st];
    } 
    while(!stk.empty()){
        println(a[stk.top()].pos);
        stk.pop();
    }
    return 0;
}