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[LeetCode] Minimum Moves to Equal Array Elements II

时间:2018-03-08 02:44:40      阅读:215      评论:0      收藏:0      [点我收藏+]

标签:ret   tco   leetcode   UI   gpo   lan   nts   incr   selected   

Given a non-empty integer array, find the minimum number of moves required to make all array elements equal, where a move is incrementing a selected element by 1 or decrementing a selected element by 1.

You may assume the array‘s length is at most 10,000.

Example:

Input:
[1,2,3]

Output:
2

Explanation:
Only two moves are needed (remember each move increments or decrements one element):

[1,2,3]  =>  [2,2,3]  =>  [2,2,2]

思路:

1、将数组排序并找出中位数

2、计算数组中每个数与中位数之差。这些差值的和就是要求的结果

class Solution {
public:
    int minMoves2(vector<int>& nums) {
        sort(nums.begin(), nums.end());
        int mid = nums[nums.size() / 2];
        int res = 0;
        for (int i = 0; i < nums.size(); i++) 
            res += abs(nums[i] - mid);
        return res;
    }
};
// 17 ms

 

[LeetCode] Minimum Moves to Equal Array Elements II

标签:ret   tco   leetcode   UI   gpo   lan   nts   incr   selected   

原文地址:https://www.cnblogs.com/immjc/p/8525927.html

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