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[LeetCode] 557. Reverse Words in a String III 翻转字符串中的单词 III

时间:2018-03-10 11:49:59      阅读:179      评论:0      收藏:0      [点我收藏+]

标签:oct   bsp   res   obj   list   any   ret   blank   solution   

Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1:

Input: "Let‘s take LeetCode contest"
Output: "s‘teL ekat edoCteeL tsetnoc"

 Note: In the string, each word is separated by single space and there will not be any extra space in the string.

151. Reverse Words in a String186. Reverse Words in a String II 的类似题目,这题是让翻转字符串里的单词。

 

Python:One Place

class Solution(object):
    def reverseWords(self, s):

        def reverse(s, begin, end):
            for i in xrange((end - begin) // 2):
                s[begin + i], s[end - 1 - i] = s[end - 1 - i], s[begin + i]

        s, i = list(s), 0
        for j in xrange(len(s) + 1):
            if j == len(s) or s[j] == ‘ ‘:
                reverse(s, i, j)
                i = j + 1
        return "".join(s)

Python:New Array

class Solution2(object):
    def reverseWords(self, s):
        reversed_words = [word[::-1] for word in s.split(‘ ‘)]
        return ‘ ‘.join(reversed_words)

C++:

class Solution {
public:
    string reverseWords(string s) {
        for (int i = 0, j = 0; j <= s.length(); ++j) {
            if (j == s.length() || s[j] == ‘ ‘) {
                reverse(s.begin() + i, s.begin() + j);
                i = j + 1;
            }
        }
        return s;
    }
};

     

类似题目:

[LeetCode] 151. Reverse Words in a String 翻转字符串中的单词

[LeetCode] 186. Reverse Words in a String II 翻转字符串中的单词 II

 

[LeetCode] 557. Reverse Words in a String III 翻转字符串中的单词 III

标签:oct   bsp   res   obj   list   any   ret   blank   solution   

原文地址:https://www.cnblogs.com/lightwindy/p/8537283.html

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