获取assets编码问题

public String read(String fileName) {
		String reultString = "";
		try {
			InputStream in = getResources().getAssets().open(fileName);

			int available = in.available();
			byte[] byte1 = new byte[available];
			in.read(byte1);
			String sssString=codetype(byte1);
			reultString = EncodingUtils.getString(byte1, sssString);
			
			Log.i("ABC", sssString+"---?---");
//			reultString = new String(byte1, "UTF-8");

		} catch (IOException e) {
			e.printStackTrace();
		}

		return reultString;
	}

// 获取文件的编码格式
	public String codetype(byte[] head) {
		String code = "";
		if (head[0] == -1 && head[1] == -2) {
			code = "UTF-16";
		} else if (head[0] == -2 && head[1] == -1) {
			code = "Unicode";
		} else if (head[0] == -17 && head[1] == -69 && head[2] == -65)
			code = "UTF-8";
		else {
			code = "gb2312";
		}
		return code;

	}