翻转数据

#include<iostream>
using namespace std;

void reverse(int c[5][5], int x, int y, int n, bool rev) {
        for (int i = x-1; i < n; i++) {
            for (int j = y-1; j < n; j++) {
                if (rev == true)
                    c[j][n - i - 1] = c[i][j];
                else
                    c[n - j - 1][i] = c[i][j];
            }
        }
    
}

int main() {
    int a[5][5];
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            a[i][j]=0;
        }
    }
    int b[4];
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            cin >> a[i][j];
        }
    }
    for (int j = 0; j < 4; j++) {
        cin >> b[j];
    }
    if (b[0] == 1) {
        if (b[1] == 2)
            reverse(a, b[2], b[3], 2, true);
        else if (b[1] == 3)
            reverse(a, b[2], b[3], 3, true);
        else {
            cout << "操作类型不合法，请重新输入：\n";
            for (int j = 0; j < 4; j++) {
                cin >> b[j];
            }
        }
    }
    else if (b[0] == 2) {
        if (b[1] == 2)
            reverse(a, b[2], b[3], 2, false);
        else if (b[1] == 3)
            reverse(a, b[2], b[3], 3, false);
        else {
            cout << "操作类型不合法，请重新输入：\n";
            for (int j = 0; j < 4; j++) {
                cin >> b[j];
            }
        }
    }
    else {
        cout << "操作类型不合法，请重新输入：\n";
        for (int j = 0; j < 4; j++) {
            cin >> b[j];
        }
    }
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            cout << a[i][j];
            if (j != 4)
                cout << " ";
        }
        cout << endl;
    }
    return 0;
}