练习题

team1 = [‘a‘,‘b‘,‘c‘]
team2 = [‘x‘,‘y‘,‘z‘]   #a 不和x对战，b 不和y,z 对战
# for i in team1:  #法一
#     for j in team2:
#         if i == ‘a‘ and j == ‘x‘:
#             continue
#         elif  i == ‘c‘ and (j == ‘y‘ or j ==‘z‘):
#             continue
#         else:
#             print(‘%s VS %s‘%(i,j))

for t1 in team1:  #法二
    if t1 == ‘a‘:
        tmp = team2[team2.index(‘x‘)+1:]  #返回x 的索引
    elif  t1 == ‘b‘:
        tmp = team2[:team2.index(‘y‘)]  #返回 y 的索引
    else:
        tmp = team2
    for t2 in tmp:
        print(‘%s VS %s‘%(t1,t2))

def func(x):
    if x > 0 :
        func(x-1)
        print(x)
func(5)
输出结果： 1 2 3 4 5  （递归）
循环删list元素

li = [1,1,2,3,4,5,6,7,8,9]

for i in li:
    if i%2!=0:
        li.remove(i)
print(li)
输出结果： [1, 2, 4, 6, 8]