[LeetCode]Jump Game II

标签：java   leetcode   

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Your goal is to reach the last index in the minimum number of jumps.

For example:
Given array A = [2,3,1,1,4]

The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)

public class Solution {
	public int jump(int[] A) {
		int index = 0;
		int step = 0;
		while(true){
			if(index+A[index]>=A.length-1){
				if(index!=A.length-1)   step++;
				break;
			}
			int step2 = 1;
			int k = index;
			for (int i = k; i <= k+A[k]; i++) {
				if (i - k + A[i] >= step2) {
					step2 = i - k + A[i];
					index = i;
				}
			}
			step++;
		}
		return step;
	}
}

[LeetCode]Jump Game II

标签：java   leetcode   

原文地址：http://blog.csdn.net/guorudi/article/details/39500083