private Hashtable<String, String> emails = new Hashtable<String, String>();
//方法一: 用entrySet()
Iterator it = emails.entrySet().iterator();
while(it.hasNext()){
Map.Entry m=(Map.Entry)it.next();
logger.info("email-" + m.getKey() + ":" + m.getValue());
}
// 方法二:jdk1.5支持,用entrySet()和For-Each循环()
for (Map.Entry<String, String> m : emails.entrySet()) {
logger.info("email-" + m.getKey() + ":" + m.getValue());
}
// 方法三:用keySet()
Iterator it = emails.keySet().iterator();
while (it.hasNext()){
String key;
key=(String)it.next();
logger.info("email-" + key + ":" + emails.get(key));
}
// 方法五:jdk1.5支持,用keySEt()和For-Each循环
for(Object m: emails.keySet()){
logger.info("email-" + m+ ":" + emails.get(m));
}
另外 我们可以先把hashMap 转为集合Collection,再迭代输出,不过得到的对象
Map aa = new HashMap();
aa.put("tmp1", new Object()); //追加 替换用同样的函数.
aa.remove("temp1"); //删除
for (Iterator i = aa.values().iterator(); i.hasNext(); ) {
Object temp = i.next();
} //遍历