解题关键:极角排序,cmp函数即可。
#include<cstdio> #include<cstring> #include<algorithm> #include<cstdlib> #include<cmath> #include<iostream> using namespace std; typedef long long ll; const double eps=1e-8; int sgn(double x){ if(fabs(x)<eps) return 0; else if(x<0) return -1; else return 1; } struct Point{ double x,y; int index; Point(){} Point(double _x,double _y){x=_x;y=_y;} Point operator-(const Point &b)const{return Point(x - b.x,y - b.y);} double operator^(const Point &b)const{return x*b.y - y*b.x;} double operator*(const Point &b)const{return x*b.x + y*b.y;} }; //*两点间距离 double dist(Point a,Point b){return sqrt((a-b)*(a-b));} int pos; Point p[100]; bool cmp(Point a,Point b){//按照极角排序的比较函数 double tmp=(a-p[pos])^(b-p[pos]); if(sgn(tmp)==0) return dist(p[pos],a)<dist(p[pos],b); else if(sgn(tmp)<0)return false; else return true; } int main(){ int T; scanf("%d",&T); int n; while(T--){ scanf("%d",&n); double x,y; for(int i=0;i<n;i++){ scanf("%d%lf%lf",&p[i].index,&p[i].x,&p[i].y); if(p[i].y<p[0].y||(p[i].y==p[0].y&&p[i].x<p[0].x)) swap(p[0],p[i]); }//p[0]为初始点 pos=0; for(int i=1;i<n;i++){ sort(p+i,p+n,cmp); pos++; } printf("%d",n); for(int i=0;i<n;i++) printf(" %d",p[i].index); printf("\n"); } return 0; }