标签:引入 first while 字典顺序 需求 个数 输出 NPU false
分支:
1.判断今天是今年第几天
1 # __author__ = "wyb" 2 # date: 2018/3/18 3 # 判断今天是今年第几天 4 import time 5 6 7 def demo(year, month, day): 8 day_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] 9 if year % 400 == 0 or (year % 4 == 0 and year % 100 != 0): 10 day_month[1] = 29 11 if month == 1: 12 return day 13 else: 14 return sum(day_month[:month - 1]) + day 15 16 17 date = time.localtime() 18 y, m, d = date[:3] 19 print(demo(y, m, d))
2.输入分数,输出分数对应等级
1 # __author__ = "wyb" 2 # date: 2018/2/21 3 # 判断学生成绩,成绩等级A-E,90分以上为A,80-89为B,70-79为C,60-69为D,60以下为E 4 5 score = int(input(">>>")) 6 if score > 100: 7 print("请输入正确的分数(0-100)") 8 elif score >= 90: 9 print("A") 10 elif score >= 80: 11 print("B") 12 elif score >= 70: 13 print("C") 14 elif score >= 60: 15 print("D") 16 elif score >= 0: 17 print("E") 18 else: 19 print("请输入正确的分数(0-100)")
3.猜年龄
普通版: 允许用户最多尝试3次,3次都没猜到的话就直接退出,如果猜对了,打印恭喜信息并退出
1 age = 21 2 count = 0 3 while count < 3: 4 guess_age = int(input("age is: ").strip()) 5 if guess_age == age: 6 print("恭喜你猜对了!") 7 break 8 elif guess_age < age: 9 print("小了") 10 elif guess_age > age: 11 print("大了") 12 count += 1 13 else: 14 print("最多可以尝试3次哦!")
升级版: 允许用户最多尝试3次,每尝试3次后如果还没猜对就问用户是否继续想玩,回答Y或y继续让其猜3次,回答N或n就退出程序,
如果猜对了就直接欢迎然后退出
1 age = 21 2 count = 0 3 flag = True 4 while flag: 5 guess_age = int(input("age is: ").strip()) 6 if guess_age == age: 7 print("恭喜你猜对了!") 8 break 9 elif guess_age < age: 10 print("小了") 11 elif guess_age > age: 12 print("大了") 13 count += 1 14 if count == 3: 15 choice = input("是否还想继续猜?(输入y继续,输入其他退出): ") 16 if choice == ‘Y‘ or choice == ‘y‘: 17 flag = True 18 count = 0 19 else: 20 flag = False
循环:
1.任意输入三个英文单词,按字典顺序输出
1 # __author__ = "wyb" 2 # date: 2018/3/10 3 4 # 任意输入三个英文单词,按字典顺序输出 5 6 # 方法1: 7 # s = input(‘x,y,z=‘) 8 # x, y, z = s.split(‘,‘) 9 # if x > y: 10 # x, y = y, x 11 # if x > z: 12 # x, z = z, x 13 # if y > z: 14 # y, z = z, y 15 # print(x, y, z) 16 17 # 方法2: 18 s = input(‘x,y,z=‘) 19 x, y, z = s.split(‘,‘) 20 x, y, z = sorted([x, y, z]) 21 print(x, y, z)
2.给一个不超出5位的正整数,判断有几位,并依次打印个位、十位、百位、千位、万位
1 # __author__ = "wyb" 2 # date: 2018/2/21 3 # (1)给一个不超出5位的正整数,判断有几位,并依次打印个位、十位、百位、千位、万位: 4 # (2)还有没有更好的打印方法? 如果需求是从万位到个位打印呢? 5 6 # (1): 7 # n = int(input(">>>")) 8 # print(n) 9 # i = 0 # 计数 10 # while n: 11 # print(n % 10) 12 # n = n//10 # 地板除法(类C语言) -> 5/2 == 2 13 # i += 1 14 # 15 # print(i) 16 17 # (2): 循环: 18 # n = int(input(">>>")) 19 # print(n) 20 # # 确定位数: 21 # if n >= 1000: 22 # if n >= 10000: 23 # num = 5 24 # else: 25 # num = 4列表 26 # else: 27 # if n >= 100: 28 # num = 3 29 # elif n >= 10: 30 # num = 2 31 # else: 32 # num = 1 33 # # 从第一位开始输出: 34 # print(num) 35 # pre = 0 36 # for i in range(num, 0, -1): 37 # cur = n//(10**(i-1)) 38 # print(cur - pre*10) 39 # pre = cur 40 41 # (2): 递归函数: 42 def func(n): 43 if n//10 == 0: 44 print(n) 45 return 46 else: 47 func(n//10) 48 print(n % 10) 49 50 n = int(input(">>>")) 51 print(n) 52 func(n)
3.打印边长为N的正方形
1 # __author__ = "wyb" 2 # date: 2018/2/21 3 # 打印边长为N的正方形: 4 5 # 长和宽上的符号个数相等但是由于每一行之间存在距离,所以看起来不像正方形 6 # N = int(input(">>>")) 7 # for i in range(0, N): 8 # if i == 0 or i == N-1: 9 # for j in range(0, N): 10 # print("*", end="") 11 # else: 12 # for j in range(0, N): 13 # if j == 0 or j == N-1: 14 # print("*", end="") 15 # else: 16 # print(" ", end="") 17 # # 换行: 18 # print("") 19 20 # 调整之后: 21 N = int(input(">>>")) 22 for i in range(0, N): 23 if i == 0 or i == N-1: 24 for j in range(0, 2*N): 25 print("*", end="") 26 else: 27 for j in range(0, 2*N): 28 if j == 0 or j == 2*N-1: 29 print("*", end="") 30 else: 31 print(" ", end="") 32 # 换行: 33 print("")
4.打印以下菱形:
*
***
*****
*******
*****
***
*
1 # __author__ = "wyb" 2 # date: 2018/2/25 3 4 # 打印以下菱形: 5 # * 6 # *** 7 # ***** 8 # ******* 9 # ***** 10 # *** 11 # * 12 13 for i in range(-3, 4): 14 if i < 0: 15 pre_space = -i 16 else: 17 pre_space = i 18 print(" " * pre_space + ‘*‘ * (7 - pre_space * 2))
5.打印菱形拓展:
*
**
***
*******
***
**
*
1 # __author__ = "wyb" 2 # date: 2018/2/25 3 4 # 打印以下图形: 5 # * 6 # ** 7 # *** 8 # ******* 9 # *** 10 # ** 11 # * 12 13 for i in range(-3, 4): 14 if i < 0: 15 print(" " * (-i) + "*" * (4 + i)) 16 elif i > 0: 17 print(" " * 3 + "*" * (4 - i)) 18 else: 19 print("*" * 7)
6.菲薄纳西数列:(1)打印100以内的菲薄纳西数列(2)求菲薄纳西数列的第101项
1 # __author__ = "wyb" 2 # date: 2018/2/21 3 # (1)打印100以内的菲薄纳西数列 4 # (2)求菲薄纳西数列的第101项 5 6 # (1): 7 number_first = 1 8 number_second = 1 9 while True: 10 print(number_first) 11 if number_second > 100: 12 break 13 number_first, number_second = number_second, number_first + number_second 14 15 # (2): 16 number_first = 1 17 number_second = 1 18 count = 1 19 while True: 20 if count == 101: 21 print(number_first) 22 count += 1 23 number_first, number_second = number_second, number_first + number_second
7.质数: (1)判断一个数是否是素数(质数)(2)求1万内的素数
1 # __author__ = "wyb" 2 # date: 2018/2/21 3 # (1)判断一个数是否是素数(质数) 4 # (2)求1万内的素数 5 # 关于质数: 一个大于1的自然数只能被1和它本身整除 6 7 # (1): 8 # number = int(input(">>>")) 9 # if number == 2: 10 # print("is prime") 11 # else: 12 # for i in range(2, number): 13 # if number % i == 0: 14 # print("not prime") 15 # break 16 # else: 17 # print("is prime") 18 19 20 # (2): 21 import time # 引入模块 22 23 count = 1 # 计数 24 print(2) 25 start_time = time.time() 26 for number in range(3, 10000, 2): 27 i = 2 28 while True: 29 i += 1 30 if number % i == 0: 31 break 32 if i * i >= number: 33 print(number) 34 count += 1 35 break 36 end_time = time.time() 37 t = end_time - start_time 38 39 print("\n", count) 40 print(t)
8.求1到5的阶乘之和: 1! + 2! + 3! + 4! + 5! == 153
1 # __author__ = "wyb" 2 # date: 2018/2/21 3 # 求1到5的阶乘之和: 1! + 2! + 3! + 4列表! + 5! == 153 4 5 # (1)递归函数求阶乘之和: 6 # def fact(number): 7 # if number <= 1: 8 # return 1 9 # else: 10 # return number * fact(number - 1) 11 # 12 # sum_fact = fact(1) + fact(2) + fact(3) + fact(4列表) + fact(5) 13 # print(sum_fact) 14 15 16 # (2)循环求阶乘之和: 17 num = 1 18 x = 0 19 for n in range(1, 6): 20 num *= n 21 x += num 22 print(x)
9.打印九九乘法表
1 # __author__ = ‘wyb‘ 2 # date: 2018/2/22 3 4 for i in range(1, 10): 5 for j in range(1, i+1): 6 print(str(j) + " X " + str(i) + " = " + str(i * j) + ‘\t‘, end=‘ ‘) 7 print()
标签:引入 first while 字典顺序 需求 个数 输出 NPU false
原文地址:https://www.cnblogs.com/wyb666/p/8796734.html