标签:lan cto htm site min c++ bool lse blog
详见:https://leetcode.com/problems/pacific-atlantic-water-flow/description/
C++:
class Solution { public: vector<pair<int, int>> pacificAtlantic(vector<vector<int>>& matrix) { if (matrix.empty() || matrix[0].empty()) { return {}; } vector<pair<int, int>> res; int m = matrix.size(), n = matrix[0].size(); vector<vector<bool>> pacific(m, vector<bool>(n, false)); vector<vector<bool>> atlantic(m, vector<bool>(n, false)); for (int i = 0; i < m; ++i) { dfs(matrix, pacific, INT_MIN, i, 0); dfs(matrix, atlantic, INT_MIN, i, n - 1); } for (int i = 0; i < n; ++i) { dfs(matrix, pacific, INT_MIN, 0, i); dfs(matrix, atlantic, INT_MIN, m - 1, i); } for (int i = 0; i < m; ++i) { for (int j = 0; j < n; ++j) { if (pacific[i][j] && atlantic[i][j]) { res.push_back({i, j}); } } } return res; } void dfs(vector<vector<int>>& matrix, vector<vector<bool>>& visited, int pre, int i, int j) { int m = matrix.size(), n = matrix[0].size(); if (i < 0 || i >= m || j < 0 || j >= n || visited[i][j] || matrix[i][j] < pre) { return; } visited[i][j] = true; dfs(matrix, visited, matrix[i][j], i + 1, j); dfs(matrix, visited, matrix[i][j], i - 1, j); dfs(matrix, visited, matrix[i][j], i, j + 1); dfs(matrix, visited, matrix[i][j], i, j - 1); } };
参考:https://www.cnblogs.com/grandyang/p/5962508.html
417 Pacific Atlantic Water Flow 太平洋大西洋水流
标签:lan cto htm site min c++ bool lse blog
原文地址:https://www.cnblogs.com/xidian2014/p/8856421.html