标签:bsp continue 代码 main dtree sort printf 线段 ring
恩,这区间范围挺大的,需要离散化。如果TLE,还需要优化一下常数。
AC代码
#include <stdio.h> #include <string.h> #include <map> #include <set> #include <algorithm> using namespace std; const int maxn = 40000+5; typedef pair<int, int> Pii; Pii a[10000 + 5]; int b[maxn], vis[10000+5], c[maxn]; int setv[maxn << 2]; void buildTree(int o, int l, int r) { setv[o] = -1; if(l < r) { int m = (l+r) / 2; buildTree(o*2, l, m); buildTree(o*2+1, m+1, r); } } void pushDown(int o) { int lc = o*2, rc = o*2+1; if(setv[o] != -1) { setv[lc] = setv[rc] = setv[o]; } setv[o] = -1; } int ul, ur; void update(int o, int l, int r, int v) { if(ul <= l && r <= ur) { setv[o] = v; } else { pushDown(o); int m = (l+r) / 2; if(ul <= m) update(o*2, l, m, v); if(m < ur) update(o*2+1, m+1, r, v); } } void query(int o) { if(setv[o] != -1) { vis[setv[o]] = 1; return; } query(o*2); query(o*2+1); } int main() { int T, n; scanf("%d", &T); while(T--) { scanf("%d", &n); for(int i = 0; i < n; i++) { scanf("%d%d", &a[i].first, &a[i].second); b[i*2] = a[i].first; b[i*2+1] = a[i].second; } sort(b, b+2*n); int cnt = 0; c[0] = b[0]; cnt = 1; for(int i = 1; i < 2*n; i++) { if(b[i] == b[i-1]) continue; if(b[i] - b[i-1] > 1) c[cnt++] = b[i-1] + 1; c[cnt++] = b[i]; } buildTree(1, 1, cnt); for(int i = 0; i < n; i++) { ul = lower_bound(c, c+cnt, a[i].first) - c + 1; ur = lower_bound(c, c+cnt, a[i].second) - c + 1; update(1, 1, cnt, i); } memset(vis, 0, sizeof(vis)); query(1); int ans = 0; for(int i = 0; i < n; i++) { ans += vis[i]; } printf("%d\n", ans); } return 0; }
poj2528 Mayor's posters (线段树+离散化)
标签:bsp continue 代码 main dtree sort printf 线段 ring
原文地址:https://www.cnblogs.com/flyawayl/p/8861433.html