标签:efi 第四次 ret float 结构体 include png turn class
题目6-1 计算两数的和与差
1.设计思路
(1)第一步:读懂题目
第二步:编写程序
(2):流程图
2.实验代码
#include <stdio.h> #define MAXN 10 struct student{ int num; char name[20]; int score; char grade; }; int set_grade( struct student *p, int n ); int main() { struct student stu[MAXN], *ptr; int n, i, count; ptr = stu; scanf("%d\n", &n); for(i = 0; i < n; i++){ scanf("%d%s%d", &stu[i].num, stu[i].name, &stu[i].score); } count = set_grade(ptr, n); printf("The count for failed (<60): %d\n", count); printf("The grades:\n"); for(i = 0; i < n; i++) printf("%d %s %c\n", stu[i].num, stu[i].name, stu[i].grade); return 0; } int set_grade( struct student *p, int n ){ int count = 0, i; for(i = 0;i<n;i++,p++){ if(p->score<60){ p->grade = ‘D‘; count++; } else if((p->score<70)&&(p->score>=60)){ p->grade = ‘C‘; } else if((p->score<85)&&(p->score>=70)){ p->grade = ‘B‘; } else{ p->grade = ‘A‘; } } return count; }
3
6-2 结构体数组按总分排序
1.设计思路
(1)第一步:读懂题目
第二步:编写程序
(2)流程图
略
2.实验代码
#include <stdio.h> struct student { int num; char name[15]; float score[3]; float sum; }; void calc(struct student *p,int n); void sort(struct student *p,int n); int main() { struct student stu[5]; int i,j; float f; for(i=0;i<5;i++) { scanf("%d%s",&stu[i].num,stu[i].name); for(j=0;j<3;j++) { scanf("%f",&f); stu[i].score[j]=f; } } calc(stu,5); sort(stu,5); for(i=0;i<5;i++) { printf("%5d%15s",stu[i].num,stu[i].name); printf(" %.1f %.1f %.1f %.1f\n",stu[i].score[0],stu[i].score[1],stu[i].score[2], stu[i].sum); } return 0; void calc(struct student *p,int n) { int i; for(i=0;i<n;i++,p++) { p->sum = p->score[0]+p->score[1]+p->score[2]; } } void sort(struct student *p,int n) { int i=0,j=0; struct student t; for(i=0;i<n;i++) { for(j=0;j<n-1;j++) { if(p[j].sum < p[j+1].sum) { t = p[j]; p[j] = p[j+1]; p[j+1] = t; } } } }
3.本题调试过程中遇到的问题及解决方法:
无
标签:efi 第四次 ret float 结构体 include png turn class
原文地址:https://www.cnblogs.com/abc12345/p/8892995.html