标签:can eof href pid def 1.0 sqrt \n acm
http://acm.hdu.edu.cn/showproblem.php?pid=2815
//解 K^D ≡ N mod P #include<map> #include<cmath> #include<cstdio> #include<iostream> using namespace std; map<int,int>mp; typedef long long LL; void read(int &x) { x=0; char c=getchar(); while(!isdigit(c)) c=getchar(); while(isdigit(c)) { x=x*10+c-‘0‘; c=getchar(); } } int Pow(int a,int b,int mod) { int res=1; for(;b;a=1LL*a*a%mod,b>>=1) if(b&1) res=1LL*res*a%mod; return res; } int gcd(int a,int b) { return !b ? a : gcd(b,a%b); } LL exBSGS(int A,int B,int C) { if(B==1) return 0; int k=0,tmp=1,d; while(1) { d=gcd(A,C); if(d==1) break; if(B%d) return -1; B/=d; C/=d; tmp=1LL*tmp*(A/d)%C; k++; if(tmp==B) return k; } mp.clear(); int m=ceil(sqrt(1.0*C)); mp[B]=0; int mul=B; for(int j=1;j<=m;++j) { mul=1LL*mul*A%C; mp[mul]=j; } int am=Pow(A,m,C); mul=tmp; for(int j=1;j<=m;++j) { mul=1LL*mul*am%C; if(mp.find(mul)!=mp.end()) return 1LL*j*m-mp[mul]+k; } return -1; } int main() { int k,p,n; LL d; while(scanf("%d",&k)!=EOF) { read(p); read(n); if(n>=p) { puts("Orz,I can’t find D!"); continue; } d=exBSGS(k,n,p); if(d==-1) puts("Orz,I can’t find D!"); else cout<<d<<‘\n‘; } }
标签:can eof href pid def 1.0 sqrt \n acm
原文地址:https://www.cnblogs.com/TheRoadToTheGold/p/8973001.html