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976 C. Nested Segments

时间:2018-05-01 23:25:34      阅读:216      评论:0      收藏:0      [点我收藏+]

标签:clip   index   dimen   assert   queue   max   operator   bool   integer   

You are given a sequence a1,?a2,?...,?an of one-dimensional segments numbered 1 through n. Your task is to find two distinct indices i and j such that segment ai lies within segment aj.

Segment [l1,?r1] lies within segment [l2,?r2] iff l1?≥?l2 and r1?≤?r2.

Print indices i and j. If there are multiple answers, print any of them. If no answer exists, print -1 -1.

Input

The first line contains one integer n (1?≤?n?≤?3·105) — the number of segments.

Each of the next n lines contains two integers li and ri (1?≤?li?≤?ri?≤?109) — the i-th segment.

Output

Print two distinct indices i and j such that segment ai lies within segment aj. If there are multiple answers, print any of them. If no answer exists, print -1 -1.

Examples
Input
Copy
5
1 10
2 9
3 9
2 3
2 9
Output
Copy
2 1
Input
Copy
3
1 5
2 6
6 20
Output
Copy
-1 -1
寻找是否存在一个段包含在另一个段里,输出段的编号
#include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <vector>
#include <queue>
#include <stack>
#include <cstdlib>
#include <iomanip>
#include <cmath>
#include <cassert>
#include <ctime>
#include <map>
#include <set>
using namespace std;
#pragma comment(linker, "/stck:1024000000,1024000000")
#define lowbit(x) (x&(-x))
#define max(x,y) (x>=y?x:y)
#define min(x,y) (x<=y?x:y)
#define MAX 100000000000000000
#define MOD 1000000007
#define pi acos(-1.0)
#define ei exp(1)
#define PI 3.1415926535897932384626433832
#define ios() ios::sync_with_stdio(true)
#define INF 0x3f3f3f3f
#define mem(a) ((a,0,sizeof(a)))
typedef long long ll;
struct node
{
    int x,y,z;
    bool operator<(const node &a)
    {
        return a.x==x?a.y<y:a.x>x;
    }
}e[300006];
int n;
int main()
{
    scanf("%d",&n);
    for(int i=0;i<n;i++)
    {
        scanf("%d%d",&e[i].x,&e[i].y);
        e[i].z=i;
    }
    sort(e,e+n);
    for(int i=0;i<n-1;i++)
    {
        if(e[i].x<=e[i+1].x && e[i].y>=e[i+1].y)
        {
            printf("%d %d\n",e[i+1].z+1,e[i].z+1);
            return 0;
        }
    }
    printf("-1 -1\n");
    return 0;
}

 

976 C. Nested Segments

标签:clip   index   dimen   assert   queue   max   operator   bool   integer   

原文地址:https://www.cnblogs.com/shinianhuanniyijuhaojiubujian/p/8977281.html

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