标签:dfs size pre clu 分享 can using dde pc2
#include <iostream>
#include <cstring>
#include <cstdio>
#include <queue>
using namespace std;
int n, m, e, a[305], w[305][305], uu, vv, ww, hea[805], cnt, ss, tt, maxFlow;
int lev[805], cur[805];
const int oo=0x3f3f3f3f;
queue<int> d;
struct Edge{
int too, nxt, val;
}edge[200005];
void add_edge(int fro, int too, int val){
edge[cnt].nxt = hea[fro];
edge[cnt].too = too;
edge[cnt].val = val;
hea[fro] = cnt++;
}
void addEdge(int fro, int too, int val){
add_edge(fro, too, val);
add_edge(too, fro, 0);
}
bool bfs(){
memset(lev, 0, sizeof(lev));
lev[ss] = 1;
d.push(ss);
while(!d.empty()){
int x=d.front();
d.pop();
for(int i=hea[x]; i!=-1; i=edge[i].nxt){
int t=edge[i].too;
if(!lev[t] && edge[i].val>0){
lev[t] = lev[x] + 1;
d.push(t);
}
}
}
return lev[tt]!=0;
}
int dfs(int x, int lim){
if(x==tt) return lim;
int addFlow=0;
for(int &i=cur[x]; i!=-1; i=edge[i].nxt){
int t=edge[i].too;
if(lev[t]==lev[x]+1 && edge[i].val>0){
int tmp=dfs(t, min(lim-addFlow, edge[i].val));
edge[i].val -= tmp;
edge[i^1].val += tmp;
addFlow += tmp;
if(addFlow==lim) break;
}
}
return addFlow;
}
void dinic(){
while(bfs()){
for(int i=ss; i<=tt; i++)
cur[i] = hea[i];
maxFlow += dfs(ss, oo);
}
}
bool chk(int lim){
memset(hea, -1, sizeof(hea));
ss = 0; tt = n + m + 1;
cnt = 0;
for(int i=1; i<=n; i++){
addEdge(ss, i, 1);
for(int j=1; j<=m; j++)
if(w[a[i]][j]<=lim)
addEdge(i, n+j, 1);
}
for(int i=1; i<=m; i++)
addEdge(n+i, tt, 1);
maxFlow = 0;
dinic();
if(maxFlow!=min(n,m)) return false;
return true;
}
int main(){
cin>>n>>m>>e;
memset(w, 0x3f, sizeof(w));
for(int i=1; i<=n; i++)
scanf("%d", &a[i]);
for(int i=1; i<=m; i++)
w[i][i] = 0;
for(int i=1; i<=e; i++){
scanf("%d %d %d", &uu, &vv, &ww);
w[uu][vv] = w[vv][uu] = min(w[uu][vv], ww);
}
for(int k=1; k<=m; k++)
for(int i=1; i<=m; i++)
for(int j=1; j<=m; j++)
w[i][j] = min(w[i][j], w[i][k]+w[k][j]);
int l=0, r=258262, mid, re;
while(l<=r){
mid = (l + r) >> 1;
if(chk(mid)) re = mid, r = mid - 1;
else l = mid + 1;
}
cout<<re<<endl;
return 0;
}
标签:dfs size pre clu 分享 can using dde pc2
原文地址:https://www.cnblogs.com/poorpool/p/9004543.html