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POJ 3613 Cow Relays

时间:2014-09-26 10:38:18      阅读:237      评论:0      收藏:0      [点我收藏+]

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Cow Relays

Time Limit: 1000ms
Memory Limit: 65536KB
This problem will be judged on PKU. Original ID: 3613
64-bit integer IO format: %lld      Java class name: Main
 

For their physical fitness program, N (2 ≤ N ≤ 1,000,000) cows have decided to run a relay race using the T (2 ≤ T ≤ 100) cow trails throughout the pasture.

Each trail connects two different intersections (1 ≤ I1i ≤ 1,000; 1 ≤ I2i ≤ 1,000), each of which is the termination for at least two trails. The cows know the lengthi of each trail (1 ≤ lengthi  ≤ 1,000), the two intersections the trail connects, and they know that no two intersections are directly connected by two different trails. The trails form a structure known mathematically as a graph.

To run the relay, the N cows position themselves at various intersections (some intersections might have more than one cow). They must position themselves properly so that they can hand off the baton cow-by-cow and end up at the proper finishing place.

Write a program to help position the cows. Find the shortest path that connects the starting intersection (S) and the ending intersection (E) and traverses exactly N cow trails.

 

Input

* Line 1: Four space-separated integers: NTS, and E
* Lines 2..T+1: Line i+1 describes trail i with three space-separated integers: lengthi , I1i , and I2i

 

Output

* Line 1: A single integer that is the shortest distance from intersection S to intersection E that traverses exactly N cow trails.

 

Sample Input

2 6 6 4
11 4 6
4 4 8
8 4 9
6 6 8
2 6 9
3 8 9

Sample Output

10

Source

 
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 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstring>
 4 #include <cmath>
 5 #include <algorithm>
 6 #include <climits>
 7 #include <vector>
 8 #include <queue>
 9 #include <cstdlib>
10 #include <string>
11 #include <set>
12 #include <stack>
13 #define LL long long
14 #define pii pair<int,int>
15 #define INF 0x3f3f3f3f
16 using namespace std;
17 int lisan[2010],n = 0,k,t,s,e;
18 struct Matrix {
19     int m[210][210];
20     Matrix() {
21         for(int i = 0; i < 210; i++)
22             for(int j = 0; j < 210; j++)
23                 m[i][j] = INF;
24     }
25 };
26 Matrix mul(Matrix &x,Matrix &y) {
27     Matrix z;
28     for(int k = 1; k <= n; k++){
29         for(int i = 1; i <= n; i++){
30             for(int j = 1; j <= n; j++)
31                 z.m[i][j] = min(z.m[i][j],x.m[i][k]+y.m[k][j]);
32         }
33     }
34     return z;
35 }
36 Matrix fastPow(Matrix x,int index){
37     Matrix y;
38     for(int i = 0; i <= n; i++) y.m[i][i] = 0;
39     while(index){
40         if(index&1) y = mul(y,x);
41         index >>= 1;
42         x = mul(x,x);
43     }
44     return y;
45 }
46 int main() {
47     Matrix now;
48     int w,u,v;
49     scanf("%d %d %d %d",&k,&t,&s,&e);
50     while(t--){
51         scanf("%d %d %d",&w,&u,&v);
52         if(!lisan[u]) lisan[u] = ++n;
53         if(!lisan[v]) lisan[v] = ++n;
54         now.m[lisan[u]][lisan[v]] = now.m[lisan[v]][lisan[u]] = w;
55     }
56     now = fastPow(now,k);
57     printf("%d\n",now.m[lisan[s]][lisan[e]]);
58     return 0;
59 }
View Code

 

POJ 3613 Cow Relays

标签:des   style   blog   http   color   io   os   java   ar   

原文地址:http://www.cnblogs.com/crackpotisback/p/3994122.html

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