连接查询

标签：tin   left join   nio   union   join   select   rom   查询   microsoft   

1、差集。

select c.id,c.num from
(select a.`村寨id` id, count(1) num from 农户签约详细信息 a group by a.`村寨id`) c
left join
(select b.`村寨id` id, count(1) num from 房间 b group by b.`村寨id`)d
on c.id = d.id
where c.num < d.num;

SELECT DISTINCT t.id FROM
(
select a.`村寨id` id, count(1) num from 农户签约详细信息 a group by a.`村寨id`
UNION ALL
select b.`村寨id` id, count(1) num from 房间 b group by b.`村寨id`
) t
GROUP BY t.id,t.num
HAVING count(*) <2;

连接查询

标签：tin   left join   nio   union   join   select   rom   查询   microsoft   

原文地址：https://www.cnblogs.com/igoodful/p/9026747.html