大数相加

string add(string a, string b){
    int nlength;
    int diff;
    if (a.size() > b.size()){
        nlength = a.size();
        diff = a.size() - b.size();
        b.insert(b.begin(), diff, ‘0‘);
        //cout << b << endl;
    }
    else{
        nlength = b.size();
        diff = b.size() - a.size();
        a.insert(a.begin(), diff, ‘0‘);
        //cout << a << endl;
    }
    //cout << a << endl;
    //cout << b << endl;
    //cout << c << endl;
    int takeover = 0;
    for (int i = nlength - 1; i >= 0; i--){
        int temp = a[i]-‘0‘ + b[i] - ‘0‘ + takeover;
        cout << a[i] << " " << b[i] << endl;
        cout << temp << endl;
        if (temp >= 10){
            takeover = 1;
            b[i] = temp + ‘0‘ - 10;
            
            //cout << c[j] << endl;
        }
        else{
            b[i] = temp + ‘0‘;
            takeover = 0;
            
        }
    }
    //cout << takeover<<" " << j << endl;
    if (takeover == 1)b = ‘1‘ + b;
    return b;
}

void print(string str){
    int count = 0;
    for (int i = 0; i < str.size(); i++){
        if (str[i] == ‘0‘)count++;
        else
            break;
    }
    cout << str.substr(count, str.size() - count) << endl;;
}