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HDU 2602 Bone Collectors(背包问题,模版)

时间:2018-05-13 16:53:45      阅读:156      评论:0      收藏:0      [点我收藏+]

标签:ted   time   using   hdu   table   color   iostream   rds   strong   

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 14336    Accepted Submission(s): 5688


Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
技术分享图片
 

 

Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
 

 

Output
One integer per line representing the maximum of the total value (this number will be less than 231).
 

 

Sample Input
1
5 10
1 2 3 4 5
5 4 3 2 1
 

 

Sample Output
14
 

 

Author
Teddy
 

 

Source
 

 

Recommend
lcy

 

这道题,我学会了,dp数组一定要放在主函数的外面,不然编译器就会崩!!!

这里的j起始要从0开始,这是十分恶心的地方,肯能就是volume=0也会有value!!!这个是个巨型的坑!!!!!

#include<iostream>
#include<cstring>
#include<algorithm>
using namespace std;
int dp[1200][1200];
int main()
{
    int t;
    cin>>t;
    int n,m;
    int w[1200],v[1200];
    int f1,f2;
    while(t--)
    {    
        cin>>n>>m;
        memset(w,0,sizeof(w));
        memset(v,0,sizeof(v));
        memset(dp,0,sizeof(dp));
        for(int i=1;i<=n;i++)
        {
            cin>>v[i];
        }
        for(int i=1;i<=n;i++)
        {
            cin>>w[i];
        }
        for(int i=1;i<=n;i++)
        {
            for(int j=0;j<=m;j++)
            {
                if(j<w[i]) dp[i][j]=dp[i-1][j];
                else
                {
                    f1=i;
                    f2=j;
                    dp[i][j]=max(dp[i-1][j],dp[i-1][j-w[i]]+v[i]);
                }
            }
        }
        cout<<dp[f1][f2]<<endl;
    }
    return 0;
}

 

HDU 2602 Bone Collectors(背包问题,模版)

标签:ted   time   using   hdu   table   color   iostream   rds   strong   

原文地址:https://www.cnblogs.com/sakuraXiYue/p/9032521.html

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