标签：pre style stream amp main 拆分 while 没有 clu
思路：
2的最近可以整除的数是10
所以，很关键的一点，只要是偶数，例如：
6:2*3，可以拆分为能够被2整除和能够被3整除的乘积，所以，10*111=1110
144:72*2,8*9*2,2*2*2*2*3*3，能够整除9的后面加4个0，1111111110000
java至于素数，java暴力打表
#include<stdio.h> #include <iostream> #include <string.h> #include <stdlib.h> #include <algorithm> using namespace std; string arr[220]={ "0","1","10","111","100","10","1110","1001","1000","111111111","10","11","11100","1001", "10010","1110","10000","11101","1111111110","11001","100","10101","110","110101" ,"111000","100","10010","1101111111","100100","1101101","1110","111011","100000" ,"111111","111010","10010","11111111100","111","110010","10101","1000","11111", "101010","1101101","1100","1111111110","1101010","10011","1110000","1100001", "100","100011","100100","100011","11011111110","110","1001000","11001","11011010", "11011111","11100","100101","1110110","1111011111","1000000","10010","1111110", "1101011","1110100","10000101","10010","10011","111111111000","10001","1110","11100", "1100100","1001","101010","10010011","10000","1111111101","111110","101011", "1010100","111010","11011010","11010111","11000","11010101","1111111110","1001", "11010100","10000011","100110","110010","11100000","11100001","11000010","11111111111111111001","100", "101","1000110","11100001","1001000","101010","1000110","100010011","110111111100","1001010111","110","111","10010000","1011011","110010","1101010","110110100", "10101111111","110111110","100111011","111000","11011","1001010","10001100111","11101100", "1000","11110111110","11010011","10000000","100100001","10010","101001","11111100","11101111","11010110","11011111110","11101000","10001","100001010", "110110101","100100","10011","100110","1001","1111111110000","11011010","100010","1100001","11100","110111","11100","1110001","11001000","10111110111","10010","1110110","1010100", "10101101011","100100110","100011","100000","11101111", "11111111010","1010111","1111100","1111110","1010110","11111011","10101000","10111101","111010","1111011111","110110100","1011001101","110101110","100100","110000","100101111", "110101010","11010111","11111111100","1001111","10010","100101","110101000","1110","100000110","1001011","1001100","189","110010","11101111","111000000","11001","111000010", "101010","110000100","1101000101","111111111111111110010","111000011","1000" }; //189没有暴力出来，然而，测试数据没有189 int main() { int n; while (scanf("%d", &n)!=EOF && n) { cout<<arr[n]<<endl; } return 0; }
poj-1426-Find The Multiple(打表水过)
标签：pre style stream amp main 拆分 while 没有 clu
原文地址：https://www.cnblogs.com/evidd/p/9074031.html
