标签:ace std scan int line const long IV fine
不看题解真的不会做
\(f[i]\)表示最大空闲时间
但是要逆推
方程
\(if(b[i]==0)ans[i]=ans[i+1]+1;\)
\(if(ans[i+a[q].t]>ans[i])ans[i]=ans[i+a[q].t];\)
#include<cstdio>
#include<algorithm>
#define ll long long
using namespace std;
const ll mx=10010;
ll n,k,q=1;
ll b[mx],ans[mx];
struct node{ll p,t;}a[mx];
bool cmp(node a,node b) { return a.p>b.p; }
int main(){
scanf("%lld %lld",&n,&k);
for(ll i=1;i<=k;i++)
scanf("%lld %lld",&a[i].p,&a[i].t),b[a[i].p]++;
sort(a+1,a+k+1,cmp);
for(ll i=n;i>0;i--){
if(b[i]==0)ans[i]=ans[i+1]+1;
else{
for(ll j=1;j<=b[i];j++){
if(ans[i+a[q].t]>ans[i])ans[i]=ans[i+a[q].t];
q++;
}
}
}
printf("%lld",ans[1]);
return 0;
}
标签:ace std scan int line const long IV fine
原文地址:https://www.cnblogs.com/pushinl/p/9095233.html