B - Bit++

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Problem description

The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

• Operation ++ increases the value of variable x by 1.
• Operation -- decreases the value of variable x by 1.

A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You‘re given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).

Input

The first line contains a single integer n (1?≤?n?≤?150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter ?X?). Thus, there are no empty statements. The operation and the variable can be written in any order.

Output

Print a single integer — the final value of x.

Examples

1
++X

1

2
X++
--X

0
解题思路：给X初始值为0，通过n个操作，实现加1减1运算，水过！
AC代码：

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int n,x=0;char q[5];
 6     cin>>n;
 7     while(n--){
 8         cin>>q;
 9         if(q[0]==‘+‘||q[1]==‘+‘)x++;
10         else x--;
11     }
12     cout<<x<<endl;
13     return 0;
14 }

B - Bit++

标签：cut   nal   cat   problem   character   ini   empty   number   when   

原文地址：https://www.cnblogs.com/acgoto/p/9105412.html